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o-na [289]
3 years ago
12

Log base 3 of 81 multiplied by log base 2 of 16

Mathematics
1 answer:
coldgirl [10]3 years ago
4 0
\log_381\cdot\log_216=4\cdot4=16

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Given the function f(x)=1+5x^2, calculate the following values:
astra-53 [7]

Answer:

f(a)=1+5a^2

f(a+h)=1+5a^2+10ah+5h^2

\frac{f(a+h)-f(a)}{h}=10a+5h

Step-by-step explanation:

We are given f(x)=1+5x^2.

Find f(a).  All this means is replace x in f(x)=1+5x^2 with a.

f(x)=1+5x^2

f(a)=1+5a^2

Find f(a+h). All this means is replace (a+h) in f(x)=1+5x^2 with (a+h).

f(x)=1+5x^2

f(a+h)=1+5(a+h)^2

f(a+h)=1+5(a+h)(a+h)

f(a+h)=1+5(a^2+2ah+h^2)

f(a+h)=1+5a^2+10ah+5h^2

Find \frac{f(a+h)-f(a)}{h}. So we got to put some parts together; the parts above:

\frac{f(a+h)-f(a)}{h}

\frac{(1+5a^2+10ah+5h^2)-(1+5a^2)}{h}

Now in the first ( ) I see 1+5a^2 and in the second ( ) I see 1+5a^2, so this means you have (1+5a^2)-(1+5a^2) which equals 0.

\frac{10ah+5h^2}{h}

Now assuming h is not 0. we can divide top and bottom by h.

\frac{10a+5h}{1}

10a+5h

5 0
3 years ago
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