Answer:
Explanation:
428 x 10³ Pa = 4.28 x 10⁵ Pa = 4.28 atm
We shall use the gas equation
P₁V₁ / T₁ = P₂V₂ / T₂
7.66 x 10 / ( 273 + 27 ) = 4.28 x 30 / T₂
.255 = 128.4 / T₂
T₂ = 503.53
= 503.53 - 273 = 230.53⁰C .
Caesium sulfate (cesium sulfate) is the inorganic compound and salt with the formula Cs2SO4. It is a white water-soluble solid that is used to prepare dense aqueous solutions for use in isopycnic (or "density-gradient") centrifugation. It is isostructural with potassium salt.
Answer:
680 g/m is the molar mass for the unknown, non electrolyte, compound.
Explanation:
Let's apply the formula for osmotic pressure
π = Molarity . R . T
T = T° absolute (in K)
R = Universal constant gases
π = Pressure
Molarity = mol/L
As units of R are L.atm/mol.K, we have to convert the mmHg to atm
760 mmHg is 1 atm
28.1 mmHg is (28.1 .1)/760 = 0.0369 atm
0.0369 atm = M . 0.082 L.atm/mol.K . 293K
(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M
0.0015 mol/L = Molarity
This data means the mol of solute in 1L, but we have 100mL so
Molarity . volume = mol
0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole
The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m
Answer:
2.5 moles of O₂
Explanation:
2RbNO₃⇒2RbNO₂+O₂-------------The equation is balanced
<u>Mole ratio for the equation</u>
2RbNO₃⇒2RbNO₂+O₂
2 2 1
RbNO₃:O
2:1---------------------------------------For every mole of oxygen produced ,two moles of RbNO₃ are required
<u>Given</u>
5 moles of RbNO₃ will produce ? moles of oxygen
2 moles of RbNO₃=1 mole of oxygen
5 moles of RbNO₃=?
=(5×1)/2 = 2.5 moles