Answer:
-0.1767°C (Option A)
Explanation:
Let's apply the colligative property of freezing point depression.
ΔT = Kf . m. i
i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1
m = molality (mol of solute / 1kg of solvent)
We have this data → 0.095 m
Kf is the freezing-point-depression constantm 1.86 °C/m, for water
ΔT = T° frezzing pure solvent - T° freezing solution
(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1
T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C
Answer: Hello :)
pH measures how acidic or basic a substance is.
Explanation:
<em>A pH of anything less than 7.0 is considered </em><em>Acidic</em>
<em>A pH of anything greater than 7.0 is considered </em><em>Basic</em>
<em>A pH of 7 is considered neutral because the concentrations of H+ and OH- are equivalent.</em>
<em>~</em><u>rere</u>
The mass of oxygen is 236.4 g.
Explanation:
To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.
First we calculate the molar weight of carbon dioxide:
molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2
molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole
Now we devise the following reasoning:
if in 44 g of CO₂ there are 32 g of oxygen
then in 325 g of CO₂ there are X g of oxygen
X = (32 × 325) / 44 = 236.4 g oxygen
Learn more about:
molar weight
brainly.com/question/9883301
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Answer:
31.67 mph
Explanation:
To calculate the average speed of the truck, we must first obtain the total distance travelled by the truck followed by the total time taken for the truck to cover the distance travelled.
The following data were obtained from the question include:
Total distance) = 30 + 45 + 50 + 65 = 190 miles
Total time = 1 + 2 +1 +2 = 6 hours
Average speed =.?
Average speed = Total distance / Total time
Average speed = 190 /6
Average speed = 31.67 mph
Therefore, the average speed of the truck is 31.67 mph
You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45
