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Oduvanchick [21]
3 years ago
12

If there is gravity where the International Space Station (ISS) is located above Earth, why doesn’t the space station get pulled

back down to Earth?
Physics
1 answer:
nasty-shy [4]3 years ago
7 0

Answer:

Yes. Gravity is 90% of what it is on the earth's surface. ISS moves at such high speeds that the curve of its fall will always match  the curve of the earth and so will never hit the earth.

Explanation:

The location of the International Space Station (ISS) is at an altitude of about 200 or 250 miles above the earth's surface. Since gravity decreases with altitude, it is less at that height. Gravity is still present there. Since the ISS is in orbit around the earth, the condition is of free fall. Result of this free fall is apparent weightlessness. The high speed of the ISS allows it to orbit around in such a way that the gravitational pull of the earth is equal to the centripetal force experienced by the ISS in its orbit.

The conditions which make it remain in space are similar to how the moon stays in the orbit around the earth. Moon is also in free fall but it never falls down to earth.

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Explanation:

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Compare and contrast the average kinetic energy of 0.5 L of coffee at 34ÁC,
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Compared to coffee at room temperature, the molecules of the coffee at 34°C will be moving faster and colliding with one another more frequently.
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1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True B. False
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1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

2. The maximum number of electrons allowed in a p sublevel of the 3rd principal level is? 
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3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
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What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?
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Option A

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Explanation:

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6 0
3 years ago
A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
3 years ago
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