Answer:
6:9
Step-by-step explanation:
the answer is 6:9 because 4:6' equivalent is 2:3, which is the same as 6:9
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
Step-by-step explanation:
trapezium area
A=a+b/2(h)
Whole: A=8+10/2(6)
A=54 cm
Hole: 5+7/2(3)
a=18
54cm-18cm= 36
area of shaded region is 36cm.
Since m < 1 and m < 2 are complementary angles wherein the measure of their angles add up to 90°, we can establish the following equation:
m < 1 + m < 2 = 90°
x° + 48° + 2x° = 90°
Combine like terms:
48° + 3x° = 90°
Subtract 48° from both sides:
48° - 48° + 3x° = 90° - 48°
3x = 42°
Divide both sides by 3 to solve for x:
3x/3 = 42/3
x = 14°
Plug in the value of x into the equation to fins m< 1 and m < 2:
m < 1 + m < 2 = 90°
(14° + 48°) + 2(14)° = 90°
62° + 28° = 90°
90° = 90° (True statement)
Therefore:
m < 1 = 62°
m < 2 = 28°
