Answer:
a) Mat swum 100 meters.
b)after 4 length , Mat's displacement is zero.
Explanation:
As given, Mat and David are training for the swimming team , and Length of 1 side of the pool is 25 meter.
As swimming pool will be a cube or a cuboid , so it has only 4 sides.
a)
1 length = 23 meter
⇒4 length = 4×25 = 100 meter
So, Mat swam 100 meters.
b)
As after swam 4 lengths of the pool, Mat reaches to its initial position i.e Mat come back to its starting point.
As Displacement is always measures from the starting point.
So, after 4 length , Mat's displacement is zero.
The period of physical changes to sex characteristics that marks the beginning of adolescence in males and females is Puberty.
Answer:
The answer is "Option d".
Explanation:
In the given scenario, when a surface is drawn in a magnetic field, the number of magnetic field lines that enter a surface must be equal to the number left because we know that magnetic field lines are always a closed curve hence the number of magnetic field lines that join the surface should match the total left.
Answer:
t = 3.38 s
Explanation:
We have,
Initial speed of the ball that leaves the student's hand is 16 m/s
Initially, the hand is 1.90 m above the ground.
It is required to find the time for which the ball in the air before it hits the ground. We can use the equation of kinematics as :
Here, and a=-g
The equation become:
After rearranging we get the above equation as :
It is a quadratic equation, we need to find the value of t. On solving the above equation, we get :
t = -0.115 s and t = 3.38 s (ignore t = -0.115 s )
So, the ball is in air for 3.38 seconds before it hits the ground.
Answer:
a) 1.5 × 10² kPa
b) 16.9/8.1
Explanation:
a) The pressure of the front tires is 22 psi. The appropriate conversion factor is 1 psi = 6.89 kPa. The pressure of the tires in kPa is:
22 psi × (6.89 kPa / 1 psi) = 1.5 × 10² kPa
b) Regarding the blood pressure, the minimun reading is 61 mmHg and the maximum reading is 127 mmHg. The appropriate conversion factor is 1 kPa = 7.50 mmHg. The blood pressure in kPa is:
61 mmHg × (1 kPa / 7.50 mmHg) = 8.1 kPa
127 mmHg × (1 kPa / 7.50 mmHg) = 16.9 kPa