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Anna71 [15]
3 years ago
8

How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the o

rbit of Mars is 12.6 light-minutes.
Physics
1 answer:
melisa1 [442]3 years ago
7 0

Question:

A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes

How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the orbit of Mars is 12.6 light-minutes.

Answer:

S = 5.508 × 10¹¹m

V = 2.62 × 10⁸ m/s

Explanation:

The radius of the orbit of Jupiter, Rj is 43.2 light-minutes

radius of the orbit of Mars, Rm is 12.6 light-minutes

Distance travelled S = (Rj - Rm)

= 43.2 - 12.6 = 30.6 light- minutes

= 30.6 × (3 ×10⁸m/s) × 60 s

= 5.508 × 10¹¹m

time = 35mins = (35 × 60 secs)

= 2100 secs

speed = distance/time

V = 5.508 × 10¹¹m / 2100 s

V = 2.62 × 10⁸ m/s

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Explanation:

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3 years ago
A tennis player hits a ball 2.0 m above the ground. The ball leaves his racquet with a speed of 20 m/s at an angle 5.0 ∘ above t
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Answer:

Explanation:

initial height, yo = 2 m

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As it hits the ground in time t, so put y = 0

0=2+1.74 t-4.9t^{2}

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t= \frac{1.74\pm\sqrt{1.74^{2}+4\times\2\times4.9}}{9.8}

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As this distance is more than the distance of net, so it clears the net.

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t' = 0.35 s

Let the vertical distance traveled by the ball in time t' is y'.

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y'=y_{0}+uSin\theta t'-1/2 gt'^{2}

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