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Papessa [141]
3 years ago
10

Match the type of fitness with the correct example.

Physics
2 answers:
posledela3 years ago
8 0

Answer:

an exercise that stretches your back - Flexibility

lifting a heavy object - Muscular fitness

a fast walk in the park - cardiovascular fitness

a jumping exercise that makes you breathe hard - cardiovascular fitness

touching your toes - Flexibility

moving heavy bags - Muscular fitness

running - cardiovascular fitness

You're Welcome

Explanation:

jeyben [28]3 years ago
7 0

cardiovascular fitness: 3, 4, 7

flexibility: 1, 5

muscular fitness: 2, 6

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Because plastic and rubber are known as insulators which keep metal wires protected
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What type of wave has more energy, an ultraviolet wave or an x-ray?
muminat
As the wave length increases the energy of the wave decreases as the equation that relates the c=λυ λ is the wave length and υ is the frequency (which is directly proportional to the energy).
In the wave length spectrum, x-ray has a shorter wave length, meaning that x-ray has a higher energy than ultraviolet waves.

Hope this helps.

3 0
3 years ago
What is the acceleration of an object with mass of 42.6 kg when an unbalanced force of 112 N is applied to it
lord [1]
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7 0
3 years ago
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The parietal lobe is the portion of the cerebral cortex located below the temporal lobe.
jasenka [17]

Answer:

False

Explanation:

Please see the attached file

5 0
3 years ago
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A spring is 20cm long is stretched to 25cm by a load of 50N. What will be its length when stretched by 100N. assuming that the e
IgorLugansk [536]

Answer:

Final Length = 30 cm

Explanation:

The relationship between the force applied on a string and its stretching length, within the elastic limit, is given by Hooke's Law:

F = kΔx

where,

F = Force applied

k = spring constant

Δx = change in length of spring

First, we find the spring constant of the spring. For this purpose, we have the following data:

F = 50 N

Δx = change in length = 25 cm  - 20 cm = 5 cm = 0.05 m

Therefore,

50 N = k(0.05 m)

k = 50 N/0.05 m

k = 1000 N/m

Now, we find the change in its length for F = 100 N:

100 N = (1000 N/m)Δx

Δx = (100 N)/(1000 N/m)

Δx = 0.1 m = 10 cm

but,

Δx = Final Length - Initial Length

10 cm = Final Length - 20 cm

Final Length = 10 cm + 20 cm

<u>Final Length = 30 cm</u>

6 0
3 years ago
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