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Diano4ka-milaya [45]
2 years ago
7

The rate which light flows through a given area of space is referred to as ita

Physics
1 answer:
Brilliant_brown [7]2 years ago
7 0
Hey there! 

The correct answer to your question is: Intensity

The rate which light flows through a given area of space is referred to as its intensity. I<span>ntensity and wavelength are two factors which contribute to light energy.</span>
Thank you!
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When two systems in contact are not at the same temperature, _____ occurs.
Korvikt [17]
The answer is "heat transfer."
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3 years ago
15. Missy Diwater, the former platform diver or the Ringling Brother's Circus had a speed of 25m/s when she hit the
timurjin [86]
K.E.= 1/2 x MV^2 = 1/2 x 40(kg) x (25x25) =12500J
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2 years ago
5. Salt is often spread on roads during winter to prevent ice from forming. Do you think sugar would
Margaret [11]

Answer:

No because sugar is more sweet and it would not have the benefits of salt. Think of it like how people used to put salt on meat to preserve it. Would they put sugar on? No they would not because salt is a combination of things that sugar does not have.

Explanation

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3 years ago
How do you solve 2A= 4lw+2Lh+6wH for w
gizmo_the_mogwai [7]

Answer:

\displaystyle w=\frac{A-Lh}{2l+3H}

Explanation:

Solving Equations by Isolation

We have this equation:

2A= 4lw+2Lh+6wH

Let's solve it for w step by step. First, we flip both sides

4lw+2Lh+6wH =2A

Subtracting 2Lh in both sides

4lw+2Lh+6wH-2Lh =2A-2Lh

Simplifying

4lw+6wH =2A-2Lh

Factoring w

w(4l+6H) =2A-2Lh

Dividing by (4l+6H)

\displaystyle w=\frac{2A-2Lh}{4l+6H}

Simplifying by 2:

\displaystyle \boxed{w=\frac{A-Lh}{2l+3H}}

6 0
3 years ago
A small, 150 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 5.00 kg cart at rest. After th
NemiM [27]

Answer:

Mass of larger cart will be 0.0213 m /sec

Explanation:

We have given mass of small cart m_1=150gram=0.150kg

Initial velocity of small cart v_{1i}=1.6m/sec

Mass of larger block m_2=5kg

Initial velocity of larger cart v_{2i}=0m/sec

After the collision velocity of smaller cart v_{1f}=-0.890m/sec

Now according conservation of momentum

m_1v_{1i}+m_2v_{2i}=m_1v{1f}+m_2v_{2f}

0.150\times 1.6+5\times 0=0.150\times -0.890+5\times v_{2f}

5\times v_{2f}=0.1065

v_{2f}=0.0213m/sec

5 0
3 years ago
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