Answer:
W = -1.152 mJ
Explanation:
given,
F = −α x + β x³
α = 5.2 N/m and β = 700 N/m³
Work done = ?
length of stretch = ?
we know,
W = F . ds



![W = [\dfrac{-5.2x^2}{2} +700\dfrac{x^4}{4}]_0^{0.12}](https://tex.z-dn.net/?f=W%20%3D%20%5B%5Cdfrac%7B-5.2x%5E2%7D%7B2%7D%20%2B700%5Cdfrac%7Bx%5E4%7D%7B4%7D%5D_0%5E%7B0.12%7D)
now,
![W = [\dfrac{-5.2(0.12)^2}{2} +700\dfrac{(0.12)^4}{4}]](https://tex.z-dn.net/?f=W%20%3D%20%5B%5Cdfrac%7B-5.2%280.12%29%5E2%7D%7B2%7D%20%2B700%5Cdfrac%7B%280.12%29%5E4%7D%7B4%7D%5D)
W = -0.001152 J
W = -1.152 mJ
work done by the spring is equal to W = -1.152 mJ
To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.
Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.
Part A) Conservation of the energy





Part B) Kinematic equation of linear motion,

Here
v= 0 Because at 1.5m reaches highest point, so v=0


Therefore the velocity after the collision with the floor is 3.7m/s
PART C) Total change of impulse is given as,





Answer:
Explanation:
K.E is 1/2 mv^2
Therefore KE is 300000×10000×1/2
=1500000000J
= 1500000KJ
Potential energy is mgh
Therefore PE is 300000×9.8×2000
=5,880,000,000J
=5880000KJ
Answer:
Net forces which pushes the window is 30342.78 N.
Explanation:
Given:
Dimension of the office window.
Length of the window =
m
Width of the window =
m
Area of the window = 
Difference in air pressure = Inside pressure - Outside pressure
=
atm =
atm
Conversion of the pressure in its SI unit.
⇒
atm =
Pa
⇒
atm =
Pa
We have to find the net force.
We know,
⇒ Pressure = Force/Area
⇒ 
⇒ 
⇒ Plugging the values.
⇒
⇒
Newton (N)
So,
The net forces which pushes the window is 30342.78 N.