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3 years ago

What information and measurements would you need to calculate the rate of movement?

1 answer:

8 0

When you talk about rate, you will expect that it will be in terms of a time unit. It measures how fast it is going. So, you would expect that the denominator is in time units. For the movement, you can measure this with either distance or velocity.

So, for the first variety, you would need distance and time to measure the rate of how far you go at a certain time. It is also called as velocity. For the second variety, you would need velocity and time to measure the rate of how fast you are going at a certain interval. It is also called as acceleration.

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Why physics is difficult????<br><br>Especially in Electromagnetism...

morpeh [17]

Because you have to study about electricity, first of all, and also need to study about polarity

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3 years ago

Read 2 more answers

The question on science please answer correctly

umka2103 [35]

The 5kg object 5m/s 1 m off the ground

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2 years ago

If the load on Pulley E is 20N, how much effort is needed to life it?

Mariana [72]

It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20

7 0

3 years ago

A coil is wrapped with 300 turns of wire on the perimeter of a circular frame (radius = 8.0 cm). Each turn has the same area, eq

MAVERICK [17]

Answer:

Approximately 18 volts when the magnetic field strength increases from $\rm 20\; mT$ to $\rm 80\;mT$ at a constant rate.

Explanation:

By the Faraday's Law of Induction, the EMF $\epsilon$ that a changing magnetic flux induces in a coil is:

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt}$ ,

where

$N$ is the number of turns in the coil, and
$\displaystyle \frac{d\phi}{dt}$ is the rate of change in magnetic flux through this coil.

However, for a coil the magnetic flux $\phi$ is equal to

$\phi = B \cdot A\cdot \cos{\theta}$ ,

where

$B$ is the magnetic field strength at the coil, and
$A\cdot \cos{\theta}$ is the area of the coil perpendicular to the magnetic field.

For this coil, the magnetic field is perpendicular to coil, so $\theta = 0$ and $A\cdot \cos{\theta} = A$ . The area of this circular coil is equal to $\pi\cdot r^{2} = \pi\times 8.0\times 10^{-2}\approx \rm 0.0201062\; m^{2}$ .

$A\cdot \cos{\theta} = A$ doesn't change, so the rate of change in the magnetic flux $\phi$ through the coil depends only on the rate of change in the magnetic field strength $B$ . The size of the magnetic field at the instant that $B = \rm 50\; mT$ will not matter as long as the rate of change in $B$ is constant.

$\displaystyle \begin{aligned} \frac{d\phi}{dt} &= \frac{\Delta B}{\Delta t}\times A \\&= \rm \frac{80\times 10^{-3}\; T- 20\times 10^{-3}\; T}{20\times 10^{-3}\; s}\times 0.0201062\;m^{2}\\&= \rm 0.0603186\; T\cdot m^{2}\cdot s^{-1}\end{aligned}$ .

As a result,

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt} = \rm 300 \times 0.0603186\; T\cdot m^{2}\cdot s^{-1} \approx 18\; V$ .

9 0

3 years ago

_____ have a nearly circular orbit.

WITCHER [35]

The question is poor.

It expects you to choose 'B', but things aren't nearly that simple.

We picture all of the asteroids bunched up in a neat bunch between
the orbits of Mars and Jupiter, with each asteroid following its own
nearly circular orbit. But many asteroids have wildly non-circular
'eccentric' orbits, sometimes being closer to the sun than the Earth is.
You know how you hear so much discussion about when did the Earth
get hit by an asteroid ? and when will the Earth be hit by another asteroid ?
and what will happen when the Earth is hit by an asteroid again ? None
of that would be possible if asteroids all had nearly circular orbits.

We picture comets as having these loooong skinny orbits, spending
most of every orbit waaay out in the solar system, and then dipping
close to the sun for a few days, and then going back waaaay out again.
But there are also many comets in nearly circular orbits around the sun.
You never hear anything about them, because you can never see them
without a powerful telescope, and they never do anything exciting.
So some comets could be a correct answer to this question too.

And since meteoroids are the remains of old comets, and follow the
orbit of the comet that they chipped off from, there are a lot of meteoroids
in circular orbits too, and they could also be a correct answer to this question.

8 0

3 years ago