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Marina86 [1]
4 years ago
6

What information and measurements would you need to calculate the rate of movement?

Physics
1 answer:
aliina [53]4 years ago
8 0
When you talk about rate, you will expect that it will be in terms of a time unit. It measures how fast it is going. So, you would expect that the denominator is in time units. For the movement, you can measure this with either distance or velocity.

So, for the first variety, you would need distance and time to measure the rate of how far you go at a certain time. It is also called as velocity. For the second variety, you would need velocity and time to measure the rate of how fast you are going at a certain interval. It is also called as acceleration.
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Imagine a spring made of a material that is not very elastic, so that the spring force does not satisfy Hooke’s Law, but instead
Aliun [14]

Answer:

     W = -1.152 mJ

Explanation:

given,

F = −α x + β x³

α = 5.2 N/m and β = 700 N/m³

Work done = ?

length of stretch = ?

we know,

W = F . ds

W = \intF . dx

W = \int_0^{0.12} (-\alpha x + \beta x^3).dx

W = \int_0^{0.12}(-5.2 x +700 x^3).dx

W = [\dfrac{-5.2x^2}{2} +700\dfrac{x^4}{4}]_0^{0.12}

now,

W = [\dfrac{-5.2(0.12)^2}{2} +700\dfrac{(0.12)^4}{4}]

     W = -0.001152 J

    W = -1.152 mJ

work done by the spring is equal to W = -1.152 mJ

8 0
4 years ago
A 0.500 kg ball is dropped from rest at a point 1.20 m above the floor. The ball rebounds straight upward to a height of 0.700 m
KatRina [158]

To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.

Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.

Part A) Conservation of the energy

mgh = \frac{1}{2} mv^2

v_1 = \sqrt{2gh}

v_1 = \sqrt{2(9.8)(1.20)}

v_1 = 4.84m/s

\therefore v_1 = -4.84/s \rightarrow \text{Negative direction downward}

Part B)  Kinematic equation of linear motion,

v_2^2 = u_0^2 +2a\Delta y

Here

v= 0 Because at 1.5m reaches highest point, so v=0

0 = u_2^2 +2(-9.8)(0.7)

u_2 = 3.7m/s

Therefore the velocity after the collision with the floor is 3.7m/s

PART C) Total change of impulse is given as,

J = P_2 -P_1

J = mU_2-mV_1

J = m(U_2-V_1)

J = (0.5)(3.7-(-4.84))

J = 4.27kg \cdot m/s \rightarrow \text{Upward because is positive}

6 0
4 years ago
An aircraft with the mass of 300000kg is flying at an altitude of 2000m with a speed of 100m/s
Savatey [412]

Answer:

Explanation:

K.E is 1/2 mv^2

Therefore KE is 300000×10000×1/2

=1500000000J

= 1500000KJ

Potential energy is mgh

Therefore PE is 300000×9.8×2000

=5,880,000,000J

=5880000KJ

8 0
3 years ago
Read 2 more answers
5. How fast does a 50 gram arrow need to travel to have 40 Joules of kinetic energy?​
qwelly [4]

Answer: v = 40 m/5

Explanation:

40 J = 1/2 (105) v^2

1600 = v^2

v = 40 m/5

7 0
3 years ago
An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 a
Virty [35]

Answer:

Net forces which pushes the window is 30342.78 N.

Explanation:

Given:

Dimension of the office window.

Length of the window = 3.1 m

Width of the window = 2.1 m

Area of the window = (3.1\times 2.1) = 6.51\ m^2

Difference in air pressure = Inside pressure - Outside pressure

                                           = (1.0-0.954) atm = 0.046 atm

Conversion of the pressure in its SI unit.

⇒  1 atm = 101325 Pa

⇒ 0.046 atm = 0.046\times 101325 =4660.95 Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒ Pressure=\frac{Force }{Area}

⇒ Force =Pressure\times Area

⇒ Plugging the values.

⇒ Force =4660.95\times 6.51

⇒ Force=30342.78 Newton (N)

So,

The net forces which pushes the window is 30342.78 N.

3 0
4 years ago
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