Amplitude modulation is a modulation technique used in electronic communication, most commonly for transmitting information via a radio carrier wave. In amplitude modulation, the signal strength of the carrier wave is varied in proportion to that of the message signal being transmitted. The message signal is, for example, a function of the sound to be reproduced by a loudspeaker, or the light intensity of pixels of a television screen. This technique contrasts with frequency modulation, in which the frequency of the carrier signal is varied, and phase modulation, in which its phase is varied.
AM was the earliest modulation method used to transmit voice by radio. It was developed during the first quarter of the 20th century beginning with Landell de Moura and Reginald Fessenden's radiotelephone experiments. It remains in use today in many forms of communication; for example it is used in portable two-way radios, VHF aircraft radio, citizens band radio, and in computer modems in the form of QAM. AM is often used to refer to mediumwave AM radio broadcasting.
Answer:
(a) -1.18 m/s
(b) 0.84 m/s
Explanation:
(a)
The total linear momentum before the lumberjack begins to move is zero because all parts of the system are at res
From the law of conservation of momentum
m1v1+m2v2=0 hence m1v1=-m2v2 where m1 is mass of lumberjack, v1 is velocity of lumberjeck, m2 is mass of floating log, v2 is velocity of the floating log.
Substituting M1 for 103 Kg, V1 for 2.93 m/s, M2 for 255 Kg into the above equation we obtain
103Kg*2.93 m/s=-255Kg*V2
V2=-(103 kg*2.93 m/s)/255=-1.183490196 m/s
Hence V2=-1.18 m/s
(b)
For the second log
V(M1+M2)=m1v1 where V is the common velocity
V(103 Kg+255 Kg)=103 Kg*2.93 m/s
V=(103 Kg*2.93 m/s)/(103 Kg+255 Kg)=0.842988827 m/s
V=0.84 m/s
The work done on the mass is approximately 1J
<h3>How to calculate work done on mass</h3>
From the question, we are to determine the work done on the mass
The work done can be calculated from the formula for Potential energy
Work done = P.E = mgh
Where m is the mass
g is the acceleration due to gravity (g = 10 m/s²)
h is the height
From the question,
m = 2.0 kg
h = 0.050 m
Putting the values into the question, we get
Work done = 2.0 × 10 × 0.050
Work done = 1 J
Hence, the work done on the mass is approximately 1J
Learn more on how to calculate work done here: brainly.com/question/14460830
If your mass is 50 kg (you weigh 110 pounds), and the mass of the refrigerator
is 100 kg (it weighs 220 pounds), and you're standing so that the center of
the frig and the center of you are 1 meter apart (about 3 feet), then the force
of gravity between you and the frig is about 0.0000012 ounce. That's why.
