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Kobotan [32]
3 years ago
5

Where is most of the mass of an atom located? A.in the nucleus B.in the orbits C.in the electrons Dit is split between the nucle

us and the orbits
Physics
2 answers:
ElenaW [278]3 years ago
6 0
I think it is A........................................ 
matrenka [14]3 years ago
3 0

Answer:

A. In the nucleus

Explanation:

Atom mainly consisting of its three subatomic particles

1) Electron

2) Proton

3) Neutron

as we know that mass of electron is given as

m_e = 9.11 \times 10^{-31} kg

mass of proton and neutron is approximately same and given by

m_p = m_n = 1.67 \times 10^{-27} kg

now we know that mass of electron is 10000 times smaller than the mass of neutron and proton

so major part of mass of atom is due to proton and neutron

so its whole mass is concentrated in its nucleus

correct answer would be

A. In the nucleus

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How do you find the capacitance in this?
Lostsunrise [7]

Answer:

Explanation:

parallel capacitances add directly

Series capacitances add by reciprocal of sum of reciprocals.

Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]

Ceq = [ C ] + [C / 2] + [C / 3]

Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]

Ceq = 11C/6

3 0
2 years ago
Why do scientists believe that dark matter exists even though it cannot be seen?
poizon [28]
Because although they cannot see it, they can see it's influence on objects that can be seen, and it's effects.
3 0
3 years ago
As a wave moves through a medium, particles are displaced and (2 points)
Scorpion4ik [409]

As a wave moves through a medium, particles are displaced and return to their normal position after the wave passes.

Explanation:

A wave is a traveling disturbance that  carries energy from one location to  another. All waves move in straight lines  outward and away from the source of a  disturbance. Like the radiating circular  ripples, the waves of water carry energy  away from where a rock was dropped into  the pond.

Waves can move as a single pulse or as a continuous series of waves, carrying  energy away from its source. A pulse is a single disturbance, wave, or ripple that moves  outward from the point of disturbance. A train of waves are many waves emitted over and  over again from a single source.

As waves travel through matter, they will temporarily  displace the molecules or particles in matter up-and-down  or side-to-side. Waves move the energy but they do not  carry the matter with them longitudinally as they move  through matter. Once the disturbance passes, the medium  will return to its original state or position.

Therefore, as the waves move through a medium, particles are displaced and return to their normal position after the wave passes.

7 0
3 years ago
Una placa de cobre a 20°C tiene unas dimensiones de 65cm x 78 cm. Encuentra el área de la placa a 400°C; Coeficiente de dilataci
ValentinkaMS [17]

Answer:

El área de la placa es aproximadamente 5102.752 centímetros cuadrados.

Explanation:

Asumamos que el cambio dimensional como consecuencia de la temperatura es pequeña, entonces podemos estimar el área de la placa de cobre en función de la temperatura mediante la siguiente aproximación:

A_{f} = w\cdot l \cdot [1 + 2\cdot \alpha\cdot (T_{f}-T_{o})] (1)

Donde:

w - Ancho de la placa, en centímetros.

l - Longitud de la placa, en centímetros.

\alpha - Coeficiente de dilatación, en \frac{1}{^{\circ}C}.

T_{o} - Temperatura inicial, en grados Celsius.

T_{f} - Temperatura final, en grados Celsius.

Si sabemos que w = 65\,cm, l = 78\,cm, \alpha = 17\times 10^{-6}\,\frac{1}{^{\circ}C}, T_{o} = 20\,^{\circ}C and T_{f} = 400\,^{\circ}C, entonces el área de la placa a la temperatura final:

A_{f} = (65\,cm)\cdot (78\,cm)\cdot \left[1+\left(17\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (400\,^{\circ}C-20\,^{\circ}C)\right]

A_{f} = 5102.752\,cm^{2}

El área de la placa es aproximadamente 5102.752 centímetros cuadrados.

4 0
3 years ago
weegy a 7.5kg block is placed on a table. if its bottom surface area is 0.6m2 , how much pressure does the block exert on the ta
Lesechka [4]

The pressure exerted by the block on the table is given by:

p=\frac{W}{A}

where W is the weight of the box, and A is the bottom surface area of the box.

The weight of the box is: W=mg=(7.5 kg)(9.81 m/s^2)=73.6 N

Substituting into the first equation, we find the pressure:

p=\frac{W}{A}=\frac{73.6 N}{0.6 m^2}=122.7 Pa

4 0
3 years ago
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