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tiny-mole [99]
3 years ago
5

How do I solve these?

Mathematics
1 answer:
Illusion [34]3 years ago
8 0

Answer:  x= (95/11. 82/11. -24/11)

e= ( 2 4  5 )

   ( 0 -2 -1/2)

   (0 0 -23/4)

   

           


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Guys please help me
stich3 [128]

Answer: (x + [-1], y + [1])

Step-by-step explanation:

      <em>See attached. </em>We can draw, or picture it in our heads, what the reflection would look like. Then we can pick one (or multiple to test) points and see the translation.

      We can also test with a set of points. B', (2, 4) becomes G in the transformation. G is at (1, 5)

      (1 - 2, 5 - 4) -> (-1, 1)

8 0
1 year ago
Read 2 more answers
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
If you died with braces on would they take them off?
Lady bird [3.3K]

Answer:

Uhm, I don't think so could you payed for braces or your insurance paid for them.

6 0
3 years ago
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Sunny_sXe [5.5K]

Answer:

a. 1/2

b. 5/3

c. 0

d. undefined

Step-by-step explanation:

7 0
2 years ago
A bouquet of lilies and tulips has 20 flowers.
motikmotik

Answer:8 lilies and 12 tulips; total of 20 flowers.

Step-by-step explanation:

8 lilies for $3 each equals $24. 12 tulips for $2 each equals $24. Add that together and the total for the bouquet is $48.

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