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Olegator [25]
3 years ago
15

That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

Physics
1 answer:
liraira [26]3 years ago
3 0

Answer:

The answer is "0.13562748"

Explanation:

Please find the complete question in the attached file.

Using formula:

\bold{U_s=\frac{v^2}{rg}}

Given:

r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}

put the value into the above-given formula:

U_s= \frac{14.583^2}{160 \times 9.8}

    = \frac{212.663889}{1568}\\\\=0.13562748

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