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Olegator [25]
3 years ago
15

That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

Physics
1 answer:
liraira [26]3 years ago
3 0

Answer:

The answer is "0.13562748"

Explanation:

Please find the complete question in the attached file.

Using formula:

\bold{U_s=\frac{v^2}{rg}}

Given:

r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}

put the value into the above-given formula:

U_s= \frac{14.583^2}{160 \times 9.8}

    = \frac{212.663889}{1568}\\\\=0.13562748

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Suppose the Sun moved twice the distance from Earth. Describe immediate and future changes to our planet. Justify your reasoning
Reptile [31]
Our year would now be 2.8 times longer, we would also be receiving only 1/4 of the energy from the sun that we currently do. This means that we’d now be out beyond the orbit of Mars and right at the edge of the asteroid belt, and things would rapidly get very cold with temperatures expected to drop by around 50 degrees Celsius on average, and that’s with our current atmospheric composition which would not be stable in the new conditions. And also, any living thing on earth would die.
5 0
3 years ago
A high-speed bullet train accelerates and decelerates at the rate of 10 ft/s2. its maximum cruising speed is 120 mi/h. (round yo
valina [46]
What is the maximum distance the train can travel if it accelerates from rest until it reaches its cruising speed and then runs at that speed for 15 minutes?

d = vo*t + 0.5*a*(t**2)  ..........................(vo= initial speed = 0; a= acceleration; t=time, d = distance)

Vf  = vo  + a*t      (final speed, in this case it will be the cruising speed)


Since vo = 0 (starts from rest)

t = Vf/a

d = 0 + 0.5*a*((Vf/a)**2)

d =  (0.5/a)*(Vf)**2

a = 24545 miles/h2 = 10ft/s2


d1 =  (0.5/24545 miles/h2)*(120 mi/h)**2 = 0.293 miles

From cruising speed, distance traveled after 15 minutes (0.25h)

v = d/t ...................> d2 =v*t = <span>120 mi/h (0.25h)</span> = 30 miles

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D = d1 + d2 = 0.293 + 30  miles = 30.293 miles







3 0
3 years ago
What is the difference between the experimental group and the control group? its like confusing
Doss [256]
An experimental group is the group in the experiment that receives the variable that is being tested. Only one variable is tested at a time. The control group does not receive the test variable. the experimental groups are used to find the answers in a experiment
3 0
3 years ago
A 64.9 kg sprinter starts a race with an acceleration of 3.89 m/s2. She keeps this acceleration for 17 m and then maintains the
xxMikexx [17]

Answer:

Time of race  = 10.18 s

Explanation:

She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash

Time to travel 17 m can be calculated

         s = ut + 0.5at²

         17 = 0 x t + 0.5 x 3.89 x t²

          t = 2.96 s

Velocity after 2.96 seconds

          v = 3.89 x 2.96 = 11.50 m/s

Remaining distance = 100 - 17 = 83 m

Time required to cover 83 m with a speed of 11.50 m/s

          t=\frac{83}{11.50}=7.22s

Time of race = 2.96 + 7.22 = 10.18 s

3 0
3 years ago
If earth would stop receiving heat and light about 8 min what happen
rjkz [21]

If the Sun disappeared suddenly, we wouldn't know about it for about 8 minutes ... that's how long it takes for heat and light from the Sun to get here to Earth.

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Then, after a few more minutes, we would start to notice that it was beginning to slowly get cooler, and that would continue until Earth was too cold for anything to live on it.

7 0
2 years ago
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