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2 years ago

That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

Physics

1 answer:

liraira [26]2 years ago

3 0

Answer:

The answer is " $0.13562748$ "

Explanation:

Please find the complete question in the attached file.

Using formula:

$\bold{U_s=\frac{v^2}{rg}}$

Given:

$r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}$

put the value into the above-given formula:

$U_s= \frac{14.583^2}{160 \times 9.8}$

$= \frac{212.663889}{1568}\\\\=0.13562748$

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