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Harrizon [31]
3 years ago
14

Which is bigger 40% of 200 or 1/3 of 150

Mathematics
2 answers:
e-lub [12.9K]3 years ago
7 0
Lets find out...

40% of 200.....turn ur percent to a decimal.." of " means multiply
0.40(200) = 80

1/3 of 150....remember, " of " means multiply
1/3 (50) = 50/3 = 16.67

so, as u can see, the bigger one is 40% of 200.
kirill115 [55]3 years ago
3 0
40% of 200 is bigger
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pentagon [3]

Answer:

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5 0
3 years ago
Solve x2 + 14x + 17 = –96 for x
jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

If we have: x ^ 2 + 14x + 17 = -96

We can rewrite it in the following way:

x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0

Where:

a = 1\\b = 14\\c = 113

Where we have:

x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}

x = \frac {-14 \pm \sqrt {(196-452)}} {2}

x = \frac {-14 \pm \sqrt {-256}} {2}

By definition: \sqrt {-1} = i

x = \frac {-14 \pm \sqrt {256} i} {2}

x = \frac {-14 \pm16i} {2}

x = \frac {-14} {2} \pm \frac {16i} {2}

x = -7 \pm8i

Thus, the roots are given by imaginary numbers:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i

Answer:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i


5 0
3 years ago
Read 2 more answers
A farmer has a feed trough in the shape of rectangular prism with a height of 40 cm and a base that is 30 cm wide by 200 cm long
inysia [295]

Answer:

Step-by-step explanation:

You're welcome :)

5 0
3 years ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
Pemdaswhat is the PEMDAS of 40 - 32 / 8 + 5 x - 2 ​
irina1246 [14]

Answer:

5x+34

Step-by-step explanation:

4 0
3 years ago
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