M= moles de soluto / litros de solucion
moles de soluto = M. litros de solucion
Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3
<u>61.25 grams</u> of CO can be formed from 35 grams of oxygen.
The molecular mass of oxygen is <u>16 gmol⁻¹</u>
The molecular mass of carbon monoxide is<u> 28 gmol⁻¹</u>
Explanation:
The molar mass of carbon monoxide is molar mass of C added to that of O;
12 + 16 = 28
= 28g/mol
The molar mass of oxygen is 16 g/mol while that of oxygen gas (O₂) is 32 g/mol
Since the ration oxygen to carbon monoxide is 1: 2 moles, we begin to find out how many moles of carbon monoxide are formed by 35 g of oxygen;
35/32 * 2
= 70/32 moles
Then multiply by the molar mass of carbon monoxide;
70/32 * 28
= 61.25 g
Answer:
9.35g
Explanation:
The molarity equation establishes that:
So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:
The mathematical equation that establishes the relationship between molar weight, mass and moles is:
We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:
Galvanometer:
its an instrument for detecting small electric currents.
Electric motor:
its an electrical machine that converts electrical energy into mechanical energy.
