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1 year ago

How to balance NH3+NO=N2+H2O

Chemistry

1 answer:

Kryger [21]1 year ago

3 0

Explanation:

NH₃+NO=N₂+H₂O;

NH₃+NO=N₂+6H₂O;

NH₃+6NO=N₂+6H₂O;

4NH₃+6NO=N₂+6H₂O;

4NH₃+6NO=5N₂+6H₂O.

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What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?

faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a) ml=3

(b ) ml= −4

a) -278 x $10^{-23}$ J/T

b) 3.71 x $10^{-23}$ J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x $10^{-23}$ J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x $10^{-23}$ J/T

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3 years ago

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2 years ago

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3 years ago

Read 2 more answers

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

$CuBr\rightleftharpoons Cu^++Br^-$