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garik1379 [7]
2 years ago
5

54

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
7 0

Answer:

less than 5 centimeters because it is a nonvascular plant

Explanation:

Mosses are a group of plants under the division Bryophyta. They are said to be the most primitive plant life in existence as they lack true roots, stems and leaves. They also lack vascular system, hence, they are regarded as non-vascular plants. They usually grow in very small sizes (about 0.2 - 10cm).

According to this question, Penny bought a club moss plant for her water garden and needs to know how tall the plant will grow so she know how much space it will need. Since it is a miss plant that lacks vascular tissues i.e. nonvascular, it will likely grow less than 5 centimeters in height.

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A chemistry student is given 1.00 L of a clear aqueous solution at 18.0 °C. He is told an unknown amount of a certain compound
Alex17521 [72]
Idk the answer jus wanted no ads
4 0
3 years ago
nonpolar solutes dissolve more readily in nonpolar solvents than polar solvents. Describe the interactions occuring between the
earnstyle [38]

Answer:

The interactions are known as London dispersion forces.

Explanation:

It is widely known that the electron density distribution in polar and nonpolar molecules is not uniform and not static. In most cases, the electron density in any molecule will adjust to create a spontaneous dipole. In the presence of nonpolar solute and nonpolar solvent, the spontaneous dipoles have a propagating effect on the interaction. If molecule A produces a spontaneous dipole, then the electron density in the other molecule B will react by creating an opposite spontaneous dipole. The dipoles have interactive forces known as the London dispersion forces.The magnitudes of these forces increase with increase in the surface area of the molecule. Therefore, molecules with larger surface areas will have stronger London dispersion forces than those with smaller surface areas.

8 0
3 years ago
The following equilibrium constants were determined at 1123 K:C(s) + CO2(g) ⇌ 2CO(g) K'P = 1.30 × 1014CO(g) + Cl2(g) ⇌ COCl2(g)
inn [45]

Answer:

4.68x10⁹

Explanation:

Kp is the equilibrium constant based on presure, and depends only on the gas substances. For a generic equation:

aA(g) + bB(g) ⇄ cC(g) + dD(g)

Kp = \frac{(pC)^c*(pD)^d}{(pA)^a*(pB)^b}

The reaction given can be summed to form the third one:

C(s) + CO₂(g) ⇄ 2CO (g)  K'p = 1.30x10¹⁴

CO(g) + Cl₂(g) ⇄ COCl₂ (g) K''p = 6.00x10⁻³

We need to multiply the second reaction by 2, so CO will be simplified. If we multiplied a reaction for n, the new Kp will be (Kp)ⁿ, so:

C(s) + CO₂(g) ⇄ 2CO (g)  K'p = 1.30x10¹⁴

2CO(g) + 2Cl₂(g) ⇄ 2COCl₂(g) (K''p)²= (6.00x10⁻³)²

The Kp of the reaction resulted by the sum will be: Kp = K'p*K''p

C(s) + CO₂(g) + 2Cl₂(g) ⇄  2CO(g) + 2COCl₂(g)

Kp = 1.30x10¹⁴ * (6.00x10⁻³)²

Kp = 1.30x10¹⁴*3.60x10⁻⁵

Kp = 4.68x10⁹

4 0
3 years ago
An atom contains 8 protons, 8 neutrons and 10 electrons. A second atom
topjm [15]

Answer:

both atoms are ions

Explanation:

8 0
3 years ago
What enzyme catalyses the reaction of PRPP transfer to hypoxanthine with<br> formation of IMP?
Alona [7]

Answer:

HPRT

Explanation:

HPRT catalyzes the salvage reactions of hypoxanthine and guanine with PRPP to form IMP and GMP

The formation of GMP from IMP requires oxidation at C-2 of the purine ring, followed by a glutamine-dependent amidotransferase reaction that replaces the oxygen on C-2 with an amino group to yield 2-amino,6-oxy purine nucleoside monophosphate, or as this compound is commonly known, guanosine monophosphate.

8 0
3 years ago
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