Answer:
option c is correct
Explanation:
the addition of catalyst does not effect the position or equilibrium constant and increase the forward and backward reaction in equal rates so no effect would be observed
Answer:
t = 7.58 * 10¹⁹ seconds
Explanation:
First order rate constant is given as,
k = (2.303
/t) log [A₀]
/[Aₙ]
where [A₀] is the initial concentraion of the reactant; [Aₙ] is the concentration of the reactant at time, <em>t</em>
[A₀] = 615 calories;
[Aₙ] = 615 - 480 = 135 calories
k = 2.00 * 10⁻²⁰ sec⁻¹
substituting the values in the equation of the rate constant;
2.00 * 10⁻²⁰ sec⁻¹ = (2.303/t) log (615/135)
(2.00 * 10⁻²⁰ sec⁻¹) / log (615/135) = (2.303/t)
t = 2.303 / 3.037 * 10⁻²⁰
t = 7.58 * 10¹⁹ seconds
T k = 15 + 273 = 288 K
4.6 / 13 => 0.353 atm
0.50 / 0.10 => 5 L
<span>(15 + 273) K x (13 atm / 7.6 atm) x (0.50 L / 0.10 L)
</span>
<span>= </span>2463.15 K
<span>hope this helps!</span>
To determine the volume of chlorine gas that is needed, we need to first know the reaction. It is expressed as follows:
2Na + Cl2 = 2NaCl
Then, from the amount of NaCl to be produced, we calculate the moles of Cl2 needed.
14.2 g NaCl ( 1 mol / 58.44 g ) ( 1 mol Cl2 / 2 NaCl ) = 0.1215 mol Cl2
To determine the volume of the gas, we need an equation that would relate the number of moles to volume. There are a number of equation available but some are complex equations so we assume that it is an ideal gas. We use the equation:
PV = nRT
V = nRT / P
V = 0.1215 mol ( 0.08205 L-atm / mol-K ) (45.3 +273.15 K) / 1.72 atm
V = 1.85 L Cl2 gas
The molarity of the ammonia solution is 1.38 M
<h3>Definition of molarity</h3>
Molarity is defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>Determination of the mole of NH₃</h3>
•Mass of NH₃ = 23.5 g
•Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
•Mole of NH₃ =?
Mole = mass / molar mass
Mole of NH₃ = 23.5 / 17
Mole of NH₃ = 1.38 mole
<h3>Determination of the molarity </h3>
•Mole of NH₃ = 1.38 mole
•Volume = 1 L
•Molarity of NH₃ =?
Molarity = mole / Volume
Molarity of NH₃ = 1.38 / 1
Molarity of NH₃ = 1.38 M
Learn more about molarity:
brainly.com/question/9468209
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