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ladessa [460]
4 years ago
11

How many moles of bromine atoms are in 2.60×10^2 grams of bromine?

Chemistry
1 answer:
AlladinOne [14]4 years ago
4 0
Your answer is 3.25 moles of Bromine

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If 115grams of a substance reacts with 84grams of another substance, what will be the mass of the products after the reaction?
AysviL [449]
Isn’t it 115+84 so 199
4 0
3 years ago
C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t
Veseljchak [2.6K]

Answer:

c) (12×0.9889) + (13×0.01108)

Explanation:

Given data:

Percentage of C-12 = 98.89%

Percentage of C-13 = 1.108%

Atomic mass = ?

Solution:

98.89/100 = 0.9889

1.108/ 100 = 0.01108

Atomic mass = (12×0.9889) + (13×0.01108)

Atomic mass = (11.8668 + 0.144034)

Atomic mass = 12.01084

6 0
4 years ago
Jenny wants to test the electrical conductivity of two substances dissolved in water. She is preparing the containers for the ex
katen-ka-za [31]

Answer:

Volume of the solutions

This is the most important factor for her to control.

3 0
3 years ago
Calculate the mass of sodium phosphate in aqueous solution to fully react with 37 g of chromium nitrate(III) an aqueous solution
Alla [95]

Answer:

41 g

Explanation:

The equation of the reaction is;

Cr(NO3)3(aq)+Na3PO4(aq)=3NaNO3(s)+CrPO4(aq)

Number of moles of chromium nitrate = 37g/ 146.97 g/mol = 0.25 moles

1 mole of sodium phosphate reacts with 1 mole of chromium nitrate

x moles of sodium phosphate react as with 0.25 moles of chromium nitrate

x= 1 × 0.25/1

x= 0.25 moles

Mass of sodium phosphate = 0.25 moles × 163.94 g/mol

Mass of sodium phosphate = 41 g

4 0
3 years ago
What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem
Ainat [17]

Answer:  0.002 M

Explanation:

The balanced chemical equation for ionization of H_2SO_4 in water is:

H_2SO_4\rightarrow 2H^++SO_4^{2-}

According to stoichiometry :

1 mole of H_2SO_4 ionizes to give =2 mole of H^+ ions

0.001 mole of H_2SO_4 ionizes to give = \frac{2}{1}\times 0.001=0.002 mole of H^+ ions

Thus H^+ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0
3 years ago
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