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Furkat [3]
3 years ago
5

Find the sides of a triangle if two of its sides are equal, the third side is 1 1 3 cm longer than the others, and its perimeter

is 5 2 5 cm.
Mathematics
1 answer:
Helga [31]3 years ago
7 0

Answer: 137\dfrac{1}{3}\ cm,\ 137\dfrac{1}{3}\ cm,\ 250\dfrac{1}{3}\ cm

Step-by-step explanation:

Let x be the equal sides of the triangle .

The , the third side would be x+113 cm.

The perimeter is the sum of all sides of a triangle.

So , The perimeter of triangle would be  x+x+(x+113)= 3x+113 --------(1)

Since , it is given that the perimeter of triangle is 525. -----(2)

So from (1) and (2) , we have

3x+113=525\\\\ 3x=525-113=412\\\\ x=\dfrac{412}{3}=137\dfrac{1}{3}

Then, third side = 137\dfrac{1}{3}+113=250\dfrac{1}{3}\ cm

Hence , the sides of a triangle  are:137\dfrac{1}{3}\ cm,\ 137\dfrac{1}{3}\ cm,\ 250\dfrac{1}{3}\ cm

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<h2>A</h2>

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la recta:

y-yo=m(x-xo) (*)

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2 years ago
A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

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