A cell is a geographical area with a base tranceiver station at its center.
Electric field on the axis of ring on both sides is along the axial line
This electric field is away from the center on both sides
Now when an electron is placed on the axis of the ring then we will see that it will experience the electrostatic force on the electron.
The direction of force is always towards the center of the ring because here electron is a negatively charged particle and it will move opposite to the direction of electric field.
So as we release the electron from a distance of 30 cm the electron will move towards the center of ring and accelerate to its maximum speed till it will reach to the center of the ring
After that the electron will reach to the center of the ring and then moves out on the opposite side and then decelerate to zero speed as it will reach on other side.
Now after this it will again move towards the center of the ring and continue its motion similar way
So this is an oscillating motion about the center of the ring.
The acceleration is 2 mph/min
Explanation:
The acceleration of an object is the rate of change of velocity. It is defined as follows:
where
v is the final velocity
u is the initial velocity
t is the time taken for the velocity to change from u to v
For the car in this problem, we have (taking North as positive direction):
u = 25 mph
v = 35 mph
t = 5 min
Substituting into the equation, we find the acceleration:
Learn more about acceleration:
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Answer:
h = 20 m
Explanation:
given.
height, h = 10 m
Potential energy at 10 m = 50 J
Kinetic energy at 10 m = 50 J
maximum height the ball will reach, H = ?
Total energy of the system
T E = 50 J + 50 J
T E = 100 J
now,
A h = 10 m
P E = m g h
50 = m g x 10
mg = 5 ..............(1)
at the top most Point the only Potential energy will be acting on the body.
now, TE = Potential energy
100 = m g h
5 h = 100
h = 20 m
hence, the maximum height reached by the ball is equal to 20 m.
Explanation:
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