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3 years ago

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If cells are placed in a hypertonic solution containing a solute to which the membrane is impermeable what could happena)cells w

ould shrink then later reach equilibriumb)cell swell and ultimately burstc)cell show no changed)loose water and shrink

1 answer:

elena55 [62]3 years ago

6 0

Answer:

cell swell and burst(b)

Explanation:

This process is called hemolysis. it also occurs in a red blood cell.

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A homing pigeon starts from rest and accelerates uniformly at +4.00 m/s squared for 10.0 seconds. What is its velocity after the

zavuch27 [327]

' +4 m/s² ' means that the pigeon's speed is 4 m/s greater every second.

Starting from zero speed, after 10 seconds, its speed is

(10 x 4m/s) = 40 m/s.

We can't say anything about its velocity, because we have
no information regarding the direction of its flight.

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3 years ago

A 55 kg track and field athlete has an average power output of 5.4 kW during the 200 meter dash. How quickly did she finish the

olga_2 [115]

The time taken for the athlete to finish the race is 20 s (Option A)

<h3>What is power? </h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = weight × distance

Therefore,

Power = (weight × distance ) / time

<h3>How to determine the time </h3>

Mass (m) = 55 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight = mg = 55 × 9.8 = 539 N
Power (P) = 5.4 KW = 5.4 × 1000 = 5400 W
Distance (d) = 200 m
Time (t) =?

Power = (weight × distance ) / time

5400 = (539 × 200) / t

5400 = 107800 / t

Cross multiply

5400 × t = 107800

Divide both side by 5400

t = 107800 / 5400

t = 20 s

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5 0

1 year ago

Which statement is NOT true?

Nuetrik [128]

Answer:

light doesn't need a medium through which to travel because the speed of light is experimentally constant

4 0

2 years ago

If you drop a silver dollar off a building and it hits the ground in 10 seconds, how fast was the coin going just before?

Ksju [112]

V = u + at
<span>= 0 + (9.81)(10) </span>
<span>= 98.1m/s </span>

<span>Ignoring air resistance.</span>

3 0

3 years ago

Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el

rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

Explanation:

$q_1 = 21.0\mu C$

$q_1 = 47.0\mu C$

DISTANCE BETWEEN BOTH POINT CHARGE = 0.5 m

by relation for electric field we have following relation

$E = \frac{kq}{x}^2$

according to question E = 0

FROM FIGURE

x is the distance from left point charge where electric field is zero

$\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2$

solving for x we get

$\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}$

x = 0.200 m

b)electric field at half way mean x =0.25

$E =\frac{k*21*10^{-6}}{0.25^2} -\frac{k*47*10^{-6}}{0.25^2}$

E = 3.84*10^{-4} N/C

6 0

3 years ago

Read 2 more answers