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2 years ago

10

A van der Graaff generator belt takes 250 electrons up to the ball at the top every second. Assuming that there is no loss, how

long will it have to run to produce a charge of 0.015 pC on the ball?
The answer is 3.75 x 108 s but I don't know to reach it. I appreciate your help

1 answer:

Strike441 [17]2 years ago

6 0

3.75 x 108 is 2000 hope that is right

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Select the correct answer. Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 ne

sergiy2304 [10]

Acceleration of the table: B. 0.50 meters/second2

Explanation:

The problem can be solved by using Newton's second law of motion, which states that the net force acting on an object is the product of its mass and its acceleration. Mathematically:

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

For the table in this problem, we have:

$\sum F = 125 N - 120 N = 5 N$ is the net force on the table, because there are two forces of 125 N and 120 N acting in opposite directions

m = 10.0 kg is the mass of the table

Solving for a, we find the acceleration:

$a=\frac{\sum F}{m}=\frac{5}{10.0}=0.50 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

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3 years ago

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An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N, find the coefficient of kinetic

Stolb23 [73]

Answer:

The coefficient of kinetic friction = 0.026

Explanation:

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.

Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.

The external force acting on the body is in the forward direction and the friction acts in the backward direction.

Friction increases as the mass of the body increases.

Friction = $u_{k}\times m \times g$

We now equate this to the external force of 15 N.

15 = $u_{k} \times 56 \times 10$

$u_{k}$ = $\frac{15}{560}$

$u_{k}$ = 0.026

The coefficient of kinetic friction = 0.026

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3 years ago

When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted p

jarptica [38.1K]

Answer:

1.76 eV

Explanation:

Maximum kinetic energy of the emitted photo electrons = energy of the photon- work function of the metal

K.E' = (hc/λ)-∅.................. Equation 1

Where K.E' = maximum kinetic energy of the emitted photo electrons, h = Planck's constant, c = speed, λ = wave length, ∅ = work function of the metal.

make ∅ the subject of the equation

∅ = (hc/λ)-K.E'.................. Equation 2

Given: h = 6.63×10⁻³⁴ J.s, c = 3×10⁸ m/s, λ = 400 nm = 400×10⁻⁹ m, K.E' = 1.1 eV = 1.1(1.602×10⁻¹⁹) J = 1.7622×10⁻¹⁹ J

Substitute into equation 2

∅ = [6.63×10⁻³⁴(3×10⁸)/400×10⁻⁹ ]-1.7622×10⁻¹⁹

∅ = (4.973×10⁻¹⁹)-(1.7622×10⁻¹⁹)

∅ = 3.21×10⁻¹⁹ J.

The maximum kinetic energy of the photo electrons when the wave length is 330 nm is

K.E' = [6.63×10⁻³⁴( 3×10⁸ )/330×10⁻⁹]-(3.21×10⁻¹⁹)

K.E' = (6.03×10⁻¹⁹)-(3.21×10⁻¹⁹)

K.E' = 2.82×10⁻¹⁹ J

K.E' = 2.82×10⁻¹⁹/1.602×10⁻¹⁹

K.E' = 1.76 eV

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3 years ago

Finley is trying to transmit a sound wave that will travel continuously, but he is frustrated by the excess noise. What kind of

NikAS [45]

The answer is Analog

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3 years ago

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True or False? In an RL circuit, the larger the value of R (i.e. the resistance of the circuit), the longer it takes the circuit

Luba_88 [7]

Answer:

1.False

2.4 E

Explanation:

1.We have to find the statement is true or false.

We know that

Time constant, $\tau=\frac{L}{R}$

Time constant is inversely proportional to resistance R .It means when R increases then time constant decreases when R decrease then the time constant decreases.

Statement:The larger the value of R ,the longer it takes the circuit to reach its final steady- state value

It is false.

2.Energy stored in inductor,E= $\frac{1}{2}LI^2$

When I'=2I

Then, $E'=\frac{1}{2}L(2I)^2=\frac{1}{2}LI^2\times 4=4 E$

Hence,the new total energy will become 4 E.

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3 years ago