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MArishka [77]
2 years ago
10

A van der Graaff generator belt takes 250 electrons up to the ball at the top every second. Assuming that there is no loss, how

long will it have to run to produce a charge of 0.015 pC on the ball?
The answer is 3.75 x 108 s but I don't know to reach it. I appreciate your help
Physics
1 answer:
Strike441 [17]2 years ago
6 0
3.75 x 108 is 2000 hope that is right
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An acorn with a mass of 0.300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.oo m/s?
vladimir1956 [14]

Answer: 3.75 joules

Explanation:

Given that:

Mass of acorn = 0.300 kilograms

velocity = 5.oo m/s

Kinetic energy = ?

Since, kinetic energy is the energy possessed by a moving object, its value depends on the mass M and velocity V of the acorn.

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 0.300kg x (5.00m/s)^2

= 0.5 x 0.3kg x (5.00m/s)^2

= 0.15 x (5.00m/s)^2

= 3.75 joules

Thus, the kinetic energy of the falling acorn is 3.75 joules

5 0
3 years ago
A 2.0kg rock is thrown straight up into the air with a speed of 30m/s. Ignore air resistance. What is the net force acting on th
bazaltina [42]

Answer:

19.6N

Explanation:

Given parameters:

Mass of rock = 2kg

Speed  = 30m/s

Unknown:

Net force on the rock  = ?

Solution:

The net force acting on this rock is a function of the acceleration due to gravity acting upon it.

 Net force  = weight  = mass x acceleration due to gravity

 Net force  = 2 x 9.8  = 19.6N downward

6 0
2 years ago
Which one of the following is NOT a simple machine?
ivann1987 [24]
It is hammer because hammers are not examples of a simple machine
6 0
3 years ago
the moon revolves around the earth in a nearly circular orbit kept by gravitational force exerted by the earth work done will be
rodikova [14]

Answer:

Zero because the applied force is perpendicular to the motion of the object.

No work is done on an object moving is a circular path about a central attractive force.

Any work done in such a case would result in a change in the orbit.

3 0
2 years ago
A car drives at a velocity of 6.8 m/s for 250 seconds. How far did it travel?
Leno4ka [110]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

As we know, Displacement =

\qquad \sf  \dashrightarrow \: velocity  \times time

\qquad \sf  \dashrightarrow \: 6.8 \times 250

\qquad \sf  \dashrightarrow \: 1700 \: m

<h3>OR </h3>

\qquad \sf  \dashrightarrow \: 1.7 \: km

The car travelled 1700 meters ( 1.7 km )

8 0
2 years ago
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