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3 years ago

Find the x-intercept and y-intercept of the line. 4x+3y = -12

Mathematics

1 answer:

lesantik [10]3 years ago

5 0

Answer:

sorry i cant help but search it up on quizlet it will be the fith flash card

Step-by-step explanation:

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Pls help I’ll brainlest and add extra points for the correct answer

Alexandra [31]

Answer:

2x + 8x

10x

Step-by-step explanation:

Open the brackets and multiply x inside.

5 0

3 years ago

Read 2 more answers

For the function defined by y = StartFraction 1 Over x squared EndFraction, if x is doubled, what is the effect on y?

olchik [2.2K]

Answer:

a. y is quartered.

Step-by-step explanation:

y=1/x^2

when x is doubled, the equation becomes:

y=1/(2x)^2=1/(4x^2)

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2 years ago

Solve.a 12-ft ladder is leaning against a building. the bottom of the ladder is 7 ft from the building. how high is the top of t

maksim [4K]

The answer is 9.74.

6 0

3 years ago

3. A technician worked 45 hours in one week He gets paid double for every hour over 40 hours that he works. If his regular wage

8090 [49]

Answer: 41,250$ (I think)

Step-by-step explanation:

1 hour —> 825$

40 hours —> 825$ x 40 = 33,000$

The after the 40 hours he gets paid x2 and he works for 5 hours

1 hour —> 825$ x 2 = 1,650$

5 hours —> 1650$ x 5 = 8,250$

33,000 + 8,250 = 41,250$

6 0

3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago