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3 years ago

10

Solve.a 12-ft ladder is leaning against a building. the bottom of the ladder is 7 ft from the building. how high is the top of t

he ladder?

1 answer:

maksim [4K]3 years ago

6 0

The answer is 9.74.

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Y=3x, is this in standard form? And if not can i get an explanation on why not?

kodGreya [7K]

Answer: i would say no

Step-by-step explanation:

To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.

Ax+By=C

Since x

is on the right side of the equation, switch the sides so it is on the left side of the equation.

3x=y

Move y

to the left side of the equation because it contains a variable.

3x−y=0

3 0

4 years ago

Read 2 more answers

What is the value of x?

Tom [10]

Answer:

x=21

Step-by-step explanation:

100+3x+x-4=180

100+4x-4=180

96+4x=180

4x=180-96

4x=84

x=21

7 0

3 years ago

Please answer the ixl math problem for 15 points and please fill in the blanks with the correct answer please i beg will mark br

aivan3 [116]

Answer:

y = 5x + 4

Step-by-step explanation:

oooofoooofoooof

5 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

3 years ago

What is the equation of the line in slope-intercept form?

GREYUIT [131]

Y=5/2x+5 because the slope is 5/2 and the y-intercept is 5

6 0

3 years ago