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Charra [1.4K]
3 years ago
8

The ability to distinguish between acceleration and velocity will be critical to your understanding of many other concepts in th

is course. Some of the most prevalent issues arise in interpreting the sign of both the velocity and acceleration of an object. I would recommend reading through the section "The Sign of the Acceleration" carefully. An object moves with a positive acceleration. Could the object be moving with increasing speed, decreasing speed or constant speed?
Physics
1 answer:
Sauron [17]3 years ago
7 0

Answer:

Object could only be moving with increasing speed.

Explanation:

Let us consider the general formula of acceleration:

a = (Vf - Vi)/t

Vf = Vi + at   -------- equation 1

where,

Vf = Final Velocity

Vi = Initial Velocity

a = acceleration

t = time

<u>FOR POSITIVE ACCELERATION:</u>

Vf = Vi + at

since, both acceleration and time are positive quantities. Hence, it means that the final velocity of the object shall be greater than the initial velocity of the object.

Vf > Vi

It clearly shows that if an object moves with positive acceleration. <u>It could only be moving with increasing speed.</u>

Solving the same equation for negative acceleration shows that the final velocity will be less than initial velocity and object will be moving with decreasing speed.

And for the constant velocity final and initial velocities are equal and thus, acceleration will be zero.

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Through which of the following ways can heat be transferred?
Fittoniya [83]

Answer:

Heat is transfered via solid material (conduction), liquids and gases (convection), and electromagnetical waves (radiation).

Explanation:

5 0
3 years ago
Read 2 more answers
The graph below shows the velocity of a car as it attempts to set a speed record. At what point is the car the fastest?
Maksim231197 [3]

Answer:

B). 3.4 s

Explanation:

As we can see the graph is given between velocity and time

so here we can see that the velocity is changing here with time and initially for some time it moves with constant speed

Then it's speed decreases to next few second and then speed increases to its maximum value

The time after which velocity comes to its maximum value will reach after t = 3 s

so out of the all given options most correct option will be

t = 3.4 s

6 0
3 years ago
several months after a forest is cut down, a nearby river becomes much muddier than ever before. Infer how the river changed
ryzh [129]
Well this is just my opinion but I think because all the plants were gone they cant stop mud from rolling into it. Also when it rains the trees wont suck up the water, that will make it over flow and release into the land or dirt on the outsides of it. Mixing those two gives mud and it can potentially flow back in the river in largeish masses causing the river to mix with the mud makinging it more muddy. Hope this helps :D
4 0
4 years ago
A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov
Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

4 0
3 years ago
Read 2 more answers
A 6.89-nC charge is located 1.76 m from a 4.10-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
iogann1982 [59]

Answer: a) 8.2 * 10^-8 N or 82 nN and b) is repulsive

Explanation: To solve this problem we have to use the Coulomb force for two point charged, it is given by:

F=\frac{k*q1*q2}{d^{2}}

Replacing the dat we obtain F=82 nN.

The force is repulsive because the points charged have the same sign.

5 0
3 years ago
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