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Alexeev081 [22]
3 years ago
15

NEED HELP!!!!!! CAN SOMEBODY HELP ME?

Physics
1 answer:
shepuryov [24]3 years ago
4 0
1) A
2) A
3) A
4) C
8) C
9) C
10) C
11) A
12) C
13) B
14) C
15) C
16) B
17) A
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Irina18 [472]

question 1, A

Question 2, D

Question 3, B

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3 years ago
What factor has the greatest impact on flexibility?
hjlf
That would be c. :) :) :)
4 0
3 years ago
The peak value of an alternating current in a 1500-W device is 6.4 A. What is the rms voltage across it
horrorfan [7]

Answer:

6787.5 V

Explanation:

From the question,

P = IV..................... Equation 1

Where P = Power, I = rms current, V = rms voltage.

make V the subject of the equation

V = P/I................. Equation 2

Given: P = 1500 W, I = 6.4/√2 = 4.525 A

Substitute these values into equation 2

V = 1500(4.525)

V = 6787.5 V

Hence the rms voltage = 6787.5 V

7 0
3 years ago
Directions: Complete the concept map using the terms listed below.
Komok [63]

Answer:

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6 0
3 years ago
Answer True or Flase1-Electric potential due to a uniform E field doesn’t change with location.2-The equipotential surfaces asso
TEA [102]

Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}

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3 0
3 years ago
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