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Alexeev081 [22]
3 years ago
15

NEED HELP!!!!!! CAN SOMEBODY HELP ME?

Physics
1 answer:
shepuryov [24]3 years ago
4 0
1) A
2) A
3) A
4) C
8) C
9) C
10) C
11) A
12) C
13) B
14) C
15) C
16) B
17) A
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At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
Ymorist [56]

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration (a_x)=800 m/s^2

vertical component of acceleration (a_y)=880 m/s^2

mass of ball =0.37 kg

Force in horizontal direction=m\times a_x=0.37\times 800=296 N

Force in vertical direction =m\times a_y=0.37\times 880=325.6 N

Therefore net force is

F=F_x+F_y

|F|=\sqrt{296^2+325.6^2}

|F|=440.03 N

5 0
3 years ago
____ is rate of change of position.
Korvikt [17]
The RATE of change of position is speed.
3 0
3 years ago
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Name TWO WEAKNESSES of the model pictured below
Nikolay [14]

Answer:

Here are a few:

1) The orbital radius of these planets is ridiculously small an in no way representative of their actual radii.

2) The planets will only line up like that once every 5200 years, making this very unrepresentative of their usual relations - although this does make their order in distance from the sun.

3) The nebulae, comet, lens flare,  and other junk in the background is incorrect.

4) If this is meant as a representation of the planets, then Pluto should not be there as it is now considered a planetoid.

5) The planets are incorrectly scaled both to each other and to the sun.

7 0
3 years ago
Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22
natka813 [3]

Answer:

2420 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

Distance (d) = 129 m

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 22.9 × 129 × Cos 35

Wd = 22.9 × 129 × 0.8192

Wd ≈ 2420 J

Thus, the workdone is 2420 J.

3 0
3 years ago
A 2.00 kg ball is thrown upward at some unknown angle from the top of a 20.0 m high building. If the initial magnitude of the ve
Charra [1.4K]

Answer: 28.1

Explanation:

5 0
3 years ago
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