Answer:
2.068 x 10^6 m / s
Explanation:
radius, r = 5.92 x 10^-11 m
mass of electron, m = 9.1 x 10^-31 kg
charge of electron, q = 1.6 x 10^-19 C
As the electron is revolving in a circular path, it experiences a centripetal force which is balanced by the electrostatic force between the electron and the nucleus.
centripetal force = ![\frac{mv^{2}}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%7D%7Br%7D)
Electrostatic force = ![\frac{kq^{2}}{r^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bkq%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D)
where, k be the Coulombic constant, k = 9 x 10^9 Nm^2 / C^2
So, balancing both the forces we get
![\frac{kq^{2}}{r^{2}}=\frac{mv^{2}}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bkq%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%3D%5Cfrac%7Bmv%5E%7B2%7D%7D%7Br%7D)
![v=\sqrt{\frac{kq^{2}}{mr}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7Bkq%5E%7B2%7D%7D%7Bmr%7D%7D)
![v=\sqrt{\frac{9\times 10^{9}\times1.6\times 10^{-19}\times 1.6\times 10^{-19}}{9.1\times 10^{-31}\times 5.92\times10^{-11}}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B9%5Ctimes%2010%5E%7B9%7D%5Ctimes1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%205.92%5Ctimes10%5E%7B-11%7D%7D%7D)
v = 2.068 x 10^6 m / s
Thus, the speed of the electron is give by 2.068 x 10^6 m / s.
The molarity remains the same so the ratio does not change
Answer:
Balanced forces are responsible for unchanging motion. Balanced forces are forces where the effect of one force is cancelled out by another. A tug of war, where each team is pulling equally on the rope, is an example of balanced forces. The forces exerted on the rope are equal in size and opposite in direction.
Explanation:
Answer:
The answer is 39.
Explanation:
The atomic number refers to the number of protons and the atomic mass is the sum of the protons and neutrons. So, you would just do 70 - 31 and that gets you 39.
I'd answer that but I can't text graphs and tables...