Answer:
Final velocity (v) = 36 m/s
Distance traveled (s) = 2,160 m
Explanation:
Given:
Initial velocity (u) = 0
Acceleration (a) = 0.3 m/s
Time travel (t) = 2 minutes = 120 seconds
Find:
Final velocity (v) = ?
Distance traveled (s) = ?
Computation:
v = u + at
v = 0 + 0.3(120)
v = 0.3(120)
v = 36 m/s
Final velocity (v) = 36 m/s
Distance traveled (s) = ut + (1/2)at²
Distance traveled (s) = (0.5)(0.3 × 120 × 120)
Distance traveled (s) = 2,160 m
Answer:
l= 3.002 cm
Explanation:
Given that
n= 70 turns
B= 1.2 T
θ= 15°
I= 1.5 A
τ = 0.0294 N⋅m
Lets take length of sides is l.
We know that
τ = n I A B sin θ
Area of square ,A= l²
Now by putting the value
τ = n I A B sin θ
0.0294 = 70 x 1.5 x l² x 1.2 x sin 15°
l² = 0.000901 m²
l² = 9.01 cm²
l= 3.002 cm
Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:
-4.8 m / s²
Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body
F = m a
Where the bold letters indicate vectors, F is the force, m the masses and the acceleration
The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system
-W = m a
Whera is the trampoline force
Body weight is
W = mg
We substitute
- mg = ma
a =
Let's calculate
a =
a = -4.8 m / s²
The negative sign indicates that the acceleration is directed downward.
In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is
-4.8 m / s²
Learn more here: brainly.com/question/19860811
Answer:
A.) 1372 N
B.) 1316 N
C.) 1428 N
Explanation:
Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:
a. The load moves downward at a constant velocity
At constant velocity, acceleration = 0
T - mg = ma
T - mg = 0
T = mg
T = 140 × 9.8
T = 1372N
b. The load accelerates downward at a rate 0.4 m/s??
Mg - T = ma
140 × 9.8 - T = 140 × 0.4
1372 - T = 56
-T = 56 - 1372
- T = - 1316
T = 1316N
C. The load accelerates upward at a rate 0.4 m/s??
T - mg = ma
T - 140 × 9.8 = 140 × 0.4
T - 1372 = 56
T = 56 + 1372
T = 1428N
<span><em>Continental drift</em> is one of the earliest ways that geologists thought <em>continents</em><span> moved
over time. It is believed in this theory that the Earth’s movement of the
continents are relative to each other.
This idea was subsumed by the plate tectonics theory. Now, what is the
speed of the continental drift?</span></span>
Continental drift speed is 1x 10^-9 m/s.
This is equivalent to a speed of:
1 x 10 ^-9 m/s
= 1 x 0. 000 000 000 1 m/s
= 0. 000 000 000 1 m/s