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Inga [223]
4 years ago
7

Two of the three tuning forks have known frequencies. When a 510 Hz. fork and the unknown fork are struck together, four beats p

er second are heard. When a 505 Hz. fork is struck with the unknown fork, beats are produced that are too numerous to count accurately. What is the frequency of the unknown fork?
Physics
1 answer:
Vikki [24]4 years ago
3 0
4 Hz is the difference between 510 and the unknown. 
<span>Therefore the unknown is either 514 or 506. </span>

<span>If 505 and 506 were struck together, the diff would be 1 Hz </span>
<span>If 505 and 514 were struck toghether, the diff would be 9 Hz which would be difficult to count accurately, </span>

<span>Therefore the unknown is 514</span>
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The total momentum is conserved, therefore we can write:

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Solving for V, we can find the recoil velocity of the rifle:

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U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}

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