I need help on 4 and 5 please
1 answer:
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Answer:
P = 238475 N
Q = 181125
Explanation:
From the diagram attached below,
For the bridge to be at equilibrium,
Sum of upward force = sum of downward force
P+Q = 400000+19600
P+Q = 419600.................. Equation 1
Taking moment about support A
sum of clockwise moment = sum of anti clockwise moment.
400000(10-3)+19600(8-3) = Q(20-6)
2800000+98000 = 16Q
2898000 = 16Q
Q = 2898000/16
Q = 181125 N.
Substitute the value of Q into equation 1
P+181125 = 419600
P = 419600-181125
P = 238475 N.
Hence, support A exert a force of 238475 N and support B exert a force of 181125 N
Answer:
Work done, W = 5534.53 J
Explanation:
It is given that,
Force acting on the piano, F = 6157 N
It is pushed up a distance of 2.41 m friction less plank.
Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :
Since, (in vertical direction)
W = 5534.53 J
So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.