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Aleksandr-060686 [28]
3 years ago
13

CI. Design challenge: Your goal is to build a compound microscope than can at least double the size of the object. We will const

rain ourselves to values that will work later in a simulation, which has the unrealistic- for microscopes - focal lengths in meters. (Imagine instead that those values are in cm) You need to choose two converging lenses. You have available lenses with focal lengths of 2, 4, 8 and 12 m. First choose an objective lens focal length, and a distance to place the object from the lens. Then choose an eyepiece lens focal length and a distance to place the lens from the objective lens. C2. Draw your microscope design including a ray diagram. Your diagram should include: 1. Location and properties (real/virtual, upright/inverted, bigger/smaller) of the image formed by the objective. 2. Location and properties (real/virtual, upright/inverted, bigger/smaller) of the image formed by the eyepiece. C3. Calculate the magnification of your microscope

Physics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

2. 17.7cm

3. -7 that is magnification

Explanation:

See attached handwritten document

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What types of changes in motion cause acceleration?
xxTIMURxx [149]

Answer:

Change in velocity and direction over a specific period of time.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate the acceleration of an object.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

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3 years ago
Can you please solve this for me urgently want to make sure if my answers are correct?
MA_775_DIABLO [31]

Answer:

<u>Resolving</u><u> </u><u>horizontally</u><u>.</u> :

\sum d_{x} =  - (17.0 \cos 20.0) - (11.0 \cos 35.0) + (30.0 \cos 50.0) + 0 \\  { \underline{d _{x} =  -  5.702 \: m}} \\  \\  \sum d _{y} = (17.0 \sin 20.0) + 12.0 - (11.0  \sin 35.0) - (30.0 \sin 50.0) \\ { \underline{d _{y}  =  - 11.476 \: m}}

therefore, for resultant:

d =  \sqrt{ {d _{y} }^{2} + d _{x}  {}^{2}  }

substitute:

d =  \sqrt{ {( - 5.702)}^{2} +  {( - 11.476)}^{2}  }  \\  \\ d =  \sqrt{164.211}  \\  \\ { \boxed{ \boxed{ \bf{d = 12.8 \: m}}}}

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