Which type of individual retirement account should you choose if you want your contributions to be tax deductible?
1 answer:
You might be interested in
So, since she weights 6 times more on earth, say for every lb on the moon is 6lbs on earth then.
now, if 1lb on the moon is 6lbs on earth, how much is 90 earth lbs on the moon?
now, if 1lb on the moon is 6lbs on earth, how much is 90 earth lbs on the moon?
Answer:
The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.
Step-by-step explanation:
Given:
Maximum safe-weight of 37 cars = 82 tons
∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)
Mean weight of 1 car (μ) = 2 tons
Standard deviation of 37 cars = 0.8 tons
So, standard deviation of 1 car is given as:
Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?
The sample is normally distributed (Assume)
Now, let us determine the z-score of the mean weight.
The z-score is given as:
Now, finding P(x > 2.22) is same as finding P(z > 1.69).
From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.
But we need the area under the curve for z > 1.69.
So, we subtract from the total area. Total area is 1 or 100%.
So,
Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.