Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5


We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : 


Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
Answer:
C is correct
Step-by-step explanation:
Firstly, we have to solve for x in the solution set of the inequality
We have this as follows;
x + 2 ≥ 6
x ≥ 6-2
x ≥ 4
To graph this, we consider the middle sign which is greater than or equal to
So, the inequality sign has to face the right side
secondly, it has to be shaded on the point 4 due to the fact that it has the ‘equal to’ beneath the single inequality symbol
so, the correct answer here is option C
Answer:
x = 36
Step-by-step explanation:
We have the equation (2/9)x + -2 = 6.
First, notice that adding a negative number is the same as subtracting by that number. So:
(2/9)x + -2 = 6
(2/9)x - 2 = 6
Now, we need to isolate the variable. Add 2 to both sides to cancel out the -2 on the left:
(2/9)x -2 + 2 = 6 + 2
(2/9)x = 8
Now multiply both sides by 9/2 to cancel out the 2/9 on the left:
(9/2) * (2/9)x = 8 * (9/2)
x = 72/2 = 36
Thus, x = 36.
<em>~ an aesthetics lover</em>
Label your sides= hypotenuse(h),opposite(o),adjacent(a)
hypotenuse=longest(opposite the right angle)
opposite= opposite the other angle
adjacent= the other side
see which sides are involved
in this case it is adjacent and hypotenuse
so A and H
we have to use the SOHCAHTOA rule
Sin=o/h Cos=a/h Tan=o/a
we use cos because a and h are involved
Cos(15°)=62/x
rearrange the equation to find x
x= 62/cos(15)
put this in your calculator
x= 64.12
Corresponding angles are angles that are located in the same area at each intersection.
Angles 7 and 3 are vertical angles.
The answer is C, angles 3 and 11 are corresponding angles.