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3 years ago

Which of the following orders represents the ordering found in an alphanumeric outline?

Physics

2 answers:

makkiz [27]3 years ago

7 0

Answer: D

Explanation: It says that in the paragraph

son4ous [18]3 years ago

3 0

Answer:

Roman numerals, capital letters, Arabic numerals, lowercase letters

Explanation:

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Light travels from a

Mila [183]

Answer:

Non-uniform velocity as the laser light beam has got reflected by the mirror

And as the light got reflected there is a change in velocity making it non-uniform velocity

5 0

3 years ago

A system where friction is considered and calculated

katrin [286]

Answer:

the answer is B :)

Explanation:

7 0

2 years ago

What force is required to give an object with mass 300 kg an acceleration of 2

Andre45 [30]

Answer:

C. 600 N

Explanation:

Given,

mass of object (m)= 300kg

acceleration(a) =2m/s^2

We know that,

Force(F)=ma

=300*2

=600N

So,600N force is required to give an object.

5 0

3 years ago

What do bats, dolphin, and whale use to determine their location?

Flura [38]

C. Echolocation

Echolocating animals emit calls out to the environment and listen to the echoes of those calls that return from various objects near them. They use these echoes to locate and identify the objects.

5 0

3 years ago

A 2.0 kg mass is released from rest at the top of a plane at 20 degrees above the horizontal. The coefficient of kinetic frictio

4vir4ik [10]

Answer:

3.97 m/s

Explanation:

given,

mass of the object,m= 2 Kg

angle of inclination,θ = 20°

coefficient of friction,μ= 0.2

distance,L = 4 m

using work energy theorem

$W = \dfrac{1}{2}mv^2$ ..........(1)

now,

v is the speed of the box.

W is the work done on the box by a net external force.

Work done on the force

$W = F_{net}L$

$F_{net} = m g sin \theta - \mu N$

$F_{net} = m g sin \theta - \mu (mg cos \theta)$

$W = (mg sin\theta - \mu mg cos \theta)L$ ......(2)

now, equating both equation 1 and 2

$\dfrac{1}{2}mv^2 = (mg sin\theta - \mu mg cos \theta)L$

$v= \sqrt{2 (g sin\theta - \mu g cos \theta)L}$

$v= \sqrt{2(9.8\times sin 20^0 - 0.15\times 9.8 \times cos 20^0)4}$

v = 3.97 m/s

hence, the final speed of the box is equal to v = 3.97 m/s

8 0

3 years ago