Question

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 3.55 m from the base of the slide, determine the height h of the water slide.

Answer 1

Answer:

$h = 1.75 m$

Explanation:

As we know that height of the slide is given as

$h = 1.80 m$

so time taken by the child to hit the water from the slide is given as

$t = \sqrt{\frac{2h}{g}}$

now we will plug all data in it

$t = \sqrt{\frac{2(1.80)}{9.81}}$

$t = 0.605 s$

now we know that the horizontal distance moved by it is given as

$L = v_x t$

$3.55 = 0.605 v_x$

$v_x = 5.86 m/s$

now by energy conservation

$mgh = \frac{1}{2}mv^2$

so height of point A is given as

$h = \frac{v_x^2}{2g}$

$h = \frac{5.86^2}{2(9.81)}$

$h = 1.75 m$