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cestrela7 [59]
3 years ago
12

What are some differences between a human , a dog a frog and a fish name 3

Chemistry
2 answers:
Leni [432]3 years ago
8 0
There are all different species,have different shelters,and appearance.
AleksandrR [38]3 years ago
7 0
Well, human bodies differ from all those animals.
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Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons
Softa [21]

Answer:

motor oil

Explanation:

According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''

The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.

Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.

5 0
3 years ago
Read 2 more answers
How many moles and atoms are there in 60 grams of Calcium?
marta [7]

Answer:

The moles present in 60 g of calcium are 1.5 moles.

6 0
3 years ago
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How is genetic information is the same as a plum tree.
shutvik [7]

Answer:

This work was done in the European plum (Prunus domestica). The gene for PPV coat protein was separated from the PPV virus and inserted into the plum DNA, which was then regenerated and grown into complete plum trees. These trees now had the additional gene in their DNA and became resistant to PPV.

4 0
3 years ago
What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

7 0
3 years ago
What is the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30c?
kap26 [50]
Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)

.6 = n(2519.142)

Divide by 2519.142

n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl

Grams of HCl = 0.00868
3 0
3 years ago
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