During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7° c. the specific heat of water is 4.18 j/g·°c. how much heat did the reaction generate?
1 answer:
Answer is: 39,083kJ. m(coal) = 2,00g. m(water) = 500g. ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span> c(water) = 4,18 J/g·°C, <span>specific heat of water </span>Q = m(water)·ΔT·c(water), heat of reaction. Q = 500g·18,7°C·4,18J/g·°C. Q = 39083J = 39,083kJ.
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