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Maurinko [17]
3 years ago
6

During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°

c. the specific heat of water is 4.18 j/g·°c. how much heat did the reaction generate?
Chemistry
1 answer:
pantera1 [17]3 years ago
6 0
Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span>
c(water) = 4,18 J/g·°C, <span>specific heat of water
</span>Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.
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Answer:

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Explanation:

Molarity of a solution is simply defined as the mole of solute per unit litre of the solvent. Mathematically, it is represented as:

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With the above formula, let us answer the questions given above

15. Data obtained from the question include the following:

Volume of solution = 1.4L

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Therefore, the mole of the solute present in the solution is 2.66 moles.

16. Data obtained from the question include the following:

Mole of solute = 0.46 mole

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0.22 x Volume = 0.46

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