Answer:
Reagents: 1) 
2) 
, 
Mechanism: Hydroboration
Explanation:
In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.
The <u>first step</u> of this reaction is the addition of borane () to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "
". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of on the 
to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.
See figure 1
I hope it helps!
Structure is in document below.
The mononitration of p-xylene can be easily carried out at 30 degrees C.
Para-xylene<span> (</span><span>p-xylene</span><span>) is an </span>aromatic hydrocarbon, <span>one of the three </span>isomers<span> of </span>dimethylbenzene. Para-xylene is colorless and highly flammable, not acutely toxic and has some <span>narcotic effects.</span>
PV / T = P'V' / T'
V = V'
P / T = P' / T'
P = 630 mmHg
T = 100 K
P' = 1760 mmHg
T' = ?
630 / 100 = 1760 / T'
T' = 1760 / 6,3
T' = 279,36 K
T' ≈ 280 K
Answer:
304.19 g
Explanation:
M(H2) = 2*1 = 2 g/mol
54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2
3H2 + N2 ------> 2NH3
from reaction 3 mol 2 mol
given 27.05 mol x mol
x = 27.05*2/3 = 18.03 mol NH3
M(NH3) = 14 +3*1 = 17 g/mol
18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g
Closeet answer is 304.19 g.
