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ANTONII [103]
3 years ago
15

Is 2OH−+Ca2+−>2Ca(OH)2 balanced

Chemistry
2 answers:
wariber [46]3 years ago
3 0

Answer:

No.

Explanation:

No.  There is 1 atom of Ca on the left and 2 Ca's on the right  and 2 OH's on the left and 4 on the right.

The balanced equation is:

4OH-  +  2Ca2+ ---->  2Ca(OH)2.

DENIUS [597]3 years ago
3 0

Answer:

Is not balanced

Explanation:

For an equation to be balanced there must be on each side of the equation the same amount of each atom.

2 OH−  +  Ca 2+   ----> 2 Ca(OH)2

On the left we have the following amounts of atoms:

Ca = 1

O = 2

H = 2

Total charges =  0

And on the right:

Ca = 2

O = 4

H = 4

Total charges =  0

We can see that on the right we have twice as many atoms as on the left, so we can delete a molecule of Ca(OH)2

                         2 OH−  +  Ca 2+   ---->  Ca(OH)2

Now the equation is balanced because there are the same number of atoms on both sides and also the charges are equal in both sides.

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Answer:

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Explanation:

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Since camphor is a single ketone, and M+/MC = 12 ~~ 8, its molecular formula must be C10H16O, accordingly, the number of rings = (10 * 2-16)/2 = 2.

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Answer: 1. 3.23 m

2. 32.4

3. B  adding solvent  and C  removing solute

Explanation:

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