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3 years ago

Is 2OH−+Ca2+−>2Ca(OH)2 balanced

Chemistry

2 answers:

wariber [46]3 years ago

3 0

Answer:

No.

Explanation:

No. There is 1 atom of Ca on the left and 2 Ca's on the right and 2 OH's on the left and 4 on the right.

The balanced equation is:

4OH- + 2Ca2+ ----> 2Ca(OH)2.

DENIUS [597]3 years ago

3 0

Answer:

Is not balanced

Explanation:

For an equation to be balanced there must be on each side of the equation the same amount of each atom.

2 OH− + Ca 2+ ----> 2 Ca(OH)2

On the left we have the following amounts of atoms:

Ca = 1

O = 2

H = 2

Total charges = 0

And on the right:

Ca = 2

O = 4

H = 4

Total charges = 0

We can see that on the right we have twice as many atoms as on the left, so we can delete a molecule of Ca(OH)2

2 OH− + Ca 2+ ----> Ca(OH)2

Now the equation is balanced because there are the same number of atoms on both sides and also the charges are equal in both sides.

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Describe how you would obtain a beaker of pure water from salty water

Maslowich

Answer:

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid.

Explanation:

4 0

3 years ago

A 0.4322 g sample of a potassium hydroxide – lithium hydroxide mixture requires 27.10 mL of 0.3565 M HCl for its titration to th

Yuki888 [10]

The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.

The mass percent of lithium hydroxide can be calculated with the following equation:

$\% = \frac{m_{LiOH}}{m_{t}} \times 100$ (1)

Where:

$m_{t} = m_{KOH} + m_{LiOH} = 0.4322 g$ (2)

We need to find the mass of LiOH.

From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.

$\eta_{HCl} = \eta_{LiOH} + \eta_{KOH}$

$0.0271 L*0.3565 \frac{mol}{L} = \eta_{LiOH} + \eta_{KOH}$

$\eta_{LiOH} + \eta_{KOH} = 9.66 \cdot 10^{-3} \:mol$

Since mol = m/M, where M: is the molar mass and m is the mass, we have:

$\frac{m_{LiOH}}{M_{LiOH}} + \frac{m_{KOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol$ (3)

Solving equation (2) for m_{KOH} and entering into equation (3), we can find the mass of LiOH:

$\frac{m_{LiOH}}{M_{LiOH}} + \frac{0.4322 - m_{LiOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol$

$\frac{m_{LiOH}}{23.95 g/mol} + \frac{0.4322 g - m_{LiOH}}{56.1056 g/mol} = 9.66 \cdot 10^{-3} \:mol$

Solving for $m_{LiOH}$ , we have:

$m_{LiOH} = 0.082 g$

Hence, the percent lithium hydroxide is (eq 1):

$\% = \frac{0.082 g}{0.4322 g} \times 100 = 19.0 \%$

Therefore, the mass percent lithium hydroxide in the mixture is 19.0%.

Learn more about mass percent here:

brainly.com/question/6992535?referrer=searchResults

brainly.com/question/5840377?referrer=searchResults

I hope it helps you!

5 0

2 years ago

How many grams of NH3 can be produced from 2.51 mil of N2 and excess H2 ?

salantis [7]

Answer:

85.34g of NH3

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

Step 2:

Determination of the number of moles of NH3 produced by the reaction of 2.51 moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 2.51 moles of N2 will react to produce = (2.51 x 2)/1 = 5.02 moles of NH3.

Therefore, 5.02 moles of NH3 is produced from the reaction.

Step 3:

Conversion of 5.02 moles of NH3 to grams. This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Number of mole of NH3 = 5.02 moles

Mass of NH3 =..?

Mass = mole x molar Mass

Mass of NH3 = 5.02 x 17

Mass of NH3 = 85.34g

Therefore, 85.34g of NH3 is produced.

3 0

3 years ago

How many grams of sodium are needed to produce 12.5g of sodium oxide

Hatshy [7]

Answer:

25 possibly

Explanation:

I'm not too sure about this, but sodium oxide is Na2O, 2 sodium and 1 oxygen, so 12.5g * 2 is 25

If someone else comes up with a more convincing argument listen to them

4 0

3 years ago

A collection of pennies was investigated. 10.00% were found to have been minted in San Francisco with an average mass of 2.15 g

german

The average mass of the pennies in the sample is 2.16 g.

We have a set of pennies from which 10.00% have an average mass of 2.15 g and 90.00% have an average mass of 2.156 g. The average mass (am) of the whole set is a weighted average, that considers the mass (m) and the percentage (perc) of each group. We can calculate it using the following expression.

$am=\frac{\Sigma m \times perc }{100 \%} = \frac{2.15g \times 10.00\% + 2.156 g \times 90.00\% }{100\%} = 2.1554 g \approx 2.16 g$

The average mass of the pennies in the sample is 2.16 g.

You can learn more about weighted average here: brainly.com/question/18554478

5 0

3 years ago