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slega [8]
3 years ago
5

How does it? Please help

Chemistry
1 answer:
pashok25 [27]3 years ago
5 0
How does it what. i don’t know if there’s a photo but can’t see it
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A 1.200 liter solution contains 35.0 grams of potassium iodide (KI). What is the molarity of this
enot [183]

Answer:

M = 0.177

Explanation:

First, we have to find the molar mass of potassium iodine (KI).

K = 39.098

I = 126.904

Now, add these values together to get the molar mass of KI

39.098 + 126.904 = 166.0028

Now, it's time to do a grams to moles conversion.

35.0 g KI * \frac{1 mol KI}{166.0028 g KI} = \frac{35.0}{166.0028} = 0.212 mol KI

Now, we can find the molarity of this solution.

Molarity (M) = \frac{mol}{L}

M = \frac{0.212 mol KI}{1.200 L} = 0.177 M

The molarity (M) of this solution is 0.177.

3 0
3 years ago
I just need 4-8! Plz hurry!!!!!!!!!!!
RSB [31]

Answer:

4: 90N

5: 7.77777m/s

6: 4

7: 12.5609756098

8: 187.5

Explanation:

8 0
3 years ago
What is the Lewis structure of CH4​
Triss [41]

Answer:

8 Toal valence electrons.

Explanation:

For CH4 you have a total of 8 total valence electrons. Drawing the Lewis structure for CH4 (named methane) requires only single bonds. It's one of the easier Lewis structures to draw.

6 0
3 years ago
Scientific notation is___
astraxan [27]
The answer for this question is:

B. Scientific notation is used to keep track of very small and very large numbers during mathematical calculations.
7 0
4 years ago
Read 2 more answers
A sample that weighs 103.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the samp
aalyn [17]
1) we calculate the molar mass of He (helium) and Kr (Krypton).
atomic mass (He)=4 u
atomic mas (Kr)=83.8 u

Therefore the molar mass will be:
molar mass(He)=4 g/mol
molar mass(Kr)=83.8 g/mol.

1) We can find  the next equation:
mass=molar mass  x number of moles.

x=number of moles of helium
y=number of moles of helium. 

(4 g/mol) x  +(83.8 g/mol)y=103.75 g
Therefore, we have the next equation:

(1)

4x+83.8y=103.75


2) We can find other equation:

We have 30% helium atoms and 70% Kryptum atoms, therefore we have 30% Helium moles and 70% of Krypton moles.

1 mol  is always 6.022 * 10²³ atoms or molecules, (in this case atoms).

Then:
x=number of moles of helium
y=number of moles of helium.
(x+y)=number of moles of our sample.

x=30% of (x+y)

Therefore, we have this other equation:
(2)

x=0.3(x+y)


With the equations(1) and (2), we have the next system of equations:

4x+83.8y=103.75

x=0.3(x+y)  ⇒ x=0.3x+0.3y  ⇒    x-0.3x=0.3y  ⇒ 0.7 x=0.3y ⇒ x=0.3y/0.7
⇒x=3y/7

We solve this system of equations by substitution method.
x=3y/7

4(3y/7)+83.8y=103.75
lower common multiple)7
12y+586.6y=726.25
598.6y=726.25
y=1.21

x=3y/7=3(1.21)/7=0.52

We have 0.52 moles of  helium and 1.21 moles of Krypton.

1 mol=6.022 * 10²³ atoms

Total number of particles=(6.022 *10²³ atoms /1 mol) (number of moles of He+ number of moles of Kr).

Total number of particles=6.022 * 10²³ (0.52+1.21)=6.022 * 10²³ (1.73)=
=1.044 * 10²⁴ atoms.

Answer: The sample have 1.044 * 10²⁴ atoms.
6 0
4 years ago
Read 2 more answers
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