By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).
<h3>How to solve an exponential equation by logarithms</h3>
<em>Exponential</em> and <em>logarithmic</em> functions are <em>trascendental</em> functions, these are, functions that cannot be described <em>algebraically</em>. In addition, <em>logarithmic</em> functions are the <em>inverse</em> form of <em>exponential</em> functions. In this question we take advantage of this fact to solve a given expression:
- 7ˣ = 3ˣ⁺⁴ Given
- ㏒ 7ˣ = ㏒ 3ˣ⁺⁴ Definition of logarithm
- x · ㏒ 7 = (x + 4) · ㏒ 3 ㏒ aᵇ = b · ㏒ a
- x · ㏒ 7 = x · ㏒ 3 + 4 · ㏒ 3 Distributive property
- x · (㏒ 7 - ㏒ 3) = 4 · ㏒ 3 Existence of additive inverse/Modulative and associative properties
- x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3) Existence of multiplicative inverse/Modulative property/Result
By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).
To learn more on logarithms: brainly.com/question/20785664
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Answer:
The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°
Step-by-step explanation:
We are given the following from what she knows
m∠3=2⋅m∠1... 1
m∠2=2⋅m∠4 ... 2
m∠2+m∠3=360 ... 3
From what is given, we can substitute equation 1 and 2 into equation 3 as shown:
From 3:
m∠2+m∠3=360
Substituting 1 and 2 we will have:
2⋅m∠4 + 2⋅m∠1 = 360
Factor out 2 from the left hand side of the equation
2(m∠4+m∠1) = 360
Divide both sides by 2
2(m∠4+m∠1)/2 = 360/2
m∠4+m∠1 = 180°
Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°
Answer:
828382772
Step-by-step explanation:
do it your self
hope this help
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Answer:
What's the question? I'll try to help you if I know the question.
