What is that cause its not math
My guess would be 7.625% (7.63% if rounded)
Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Answer:
284.72
Step-by-step explanation:
there you go
Answer:
45x
Step-by-step explanation:
9(5x)
9 * 5 = 45
45x