PLEASE HELP ASAP 30 PTS ):

Mathematics

2 answers:

ASHA 777 [7]2 years ago

6 0

Answer:

Step-by-step explanation:

It's an exponential function but it is going in the negative direction. So now you know there has to be a negative in front of the function meaning it can only be c or d. Since we know its a exponential function. If we set x = 0, it will give us the y intercept. Which should be 1. However it is -2. Therefore it it multiplied by -2 meaning d is right answer

barxatty [35]2 years ago

6 0

Answer:

C is the correct answer

Step-by-step explanation:

A: y=0.5(3)^x

B: y=2(3)^x

C: y=-2(3)^x

D: y=-0.5(3)^x

lets replace the coeffients with (0,-2)

A: false

B: false

C: true

D: false

YaYYYY u got it! :)

You might be interested in

Please help <br><br> A. 13<br> B. 26<br> C. 40<br> D. 36<br> D. 41

Morgarella [4.7K]

The value of x is 26.

4 0

2 years ago

Read 2 more answers

Help pls im being timed

Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: $(hypothenuse)^2=(leg_1)^2+(leg_2)^2$ . And the main trigonometric ratios are:

$sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\$

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

$sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4$

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

$sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}$