1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa [96]
3 years ago
15

A small current element carrying a current of I = 1.00 A is placed at the origin given by d → l = 4.00 m m ^ j Find the magnetic

field, d → B , at the locations specified. Enter the correct magnitude and select the direction from the list. If the direction is negative, indicate this by entering the magnitude as a negative number. What is the magnitude and direction of d → B on the x ‑axis at x = 2.50 m ? magnitude: T Direction: ^ k ^ j ^ i What is the magnitude and direction of d → B on the z ‑axis at z = 5.00 m ?
Physics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

the magnitude and direction of d → B on the x ‑axis at x = 2.50 m is -6.4 × 10⁻¹¹T(Along z direction)

the magnitude and direction of d → B on the z ‑axis at z = 5.00 m is 1.6 × 10⁻¹¹T(Along x direction)

Explanation:

Use Biot, Savart, the magnetic field

d\bar{B}=\frac{U}{4\pi } \frac{i(d\bar{l}\times r)}{r^2}

Given that,

i = 1.00A

d → l = 4.00 m m ^ j

r = 2.5m

Displacement vector is

\bar{r}=x\hat i+y\hat j+z \hat k\\

\bar{r}= (2.5m) \hat i +(0m)^2 + (0m)^2

 =2.5m

on the axis of x at x = 2.5

r = \sqrt{(2.5)^2 + (0)^2 + (0)^2}

r = 2.5m

And unit vector

\hat r =\frac{\bar{r}}{r}

= \frac{2.5 \hat i}{2.5}\\\\= 1\hat i

Therefore, the magnetic field is as follow

d\bar{B}=\frac{U}{4\pi } \frac{i(d\bar{l}\times r)}{r^2}

d\bar{B} = \frac{(10^-^7)(1)(4\times10^-^3j\times i}{(2.50)^2} \\\\d\bar{B} = -6.4\times10^{-11} T

(Along z direction)

B)r = 5.00m

Displacement vector is

\bar{r}=x\hat i+y\hat j+z \hat k\\

\bar{r}= (5.00m) \hat i +(0m)^2 + (0m)^2

 =5.00m

on the axis of x at x = 5.0

r = \sqrt{(5.00)^2 + (0)^2 + (0)^2}

r = 5.00m

And unit vector

\hat r =\frac{\bar{r}}{r}

= \frac{5.00 \hat i}{5.00}\\\\= 1\hat i\\

Therefore, the magnetic field is as follow

d\bar{B}=\frac{U}{4\pi } \frac{i(d\bar{l}\times r)}{r^2}

d\bar{B} = \frac{(10^-^7)(1)(4\times10^-^3j\times i}{(5.00)^2} \\\\d\bar{B} = 1.6\times10^{-11} T

(Along x direction)

You might be interested in
A skydiver prepares to jump out of a plane. Explain how gravity and air resistance will affect the motion of the skydiver before
ahrayia [7]
Before the skydiver opens the parachute, his velocity would be increasing greatly as much as 9.8 m/s². Opening the parachute would increase the surface area to which air may cause resistance. The skydiver then reaches his terminal velocity. 
3 0
2 years ago
Read 2 more answers
What is the gravitational potential energy of a 1.3 kg book that is 473
Dmitrij [34]

Answer:

3047710272

Explanation:

556ijnhvcdse4456679908

7 0
3 years ago
Which of the following can be thought of as either a wave or a particle?
IrinaK [193]

Both matter and light have been demonstrated to exhibit wave-like and particle-like behavior.

Light as a wave: light can diffract & refract

Light as a particle: photoelectric effect, Compton scattering

Matter as a wave: Davisson-Germer experiment

Matter as a particle: find a picture of any kinematics problem in a high school physics textbook

Choice D

7 0
3 years ago
A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth.
Maksim231197 [3]

Answer:

Explanation:

We shall apply law of  conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0

\frac{-GMm}{R} +\frac{1}{2}\times  \frac{-2GMm}{R} \times0.123=\frac{-GMm}{R+h}

\frac{0.877GMm}{R} =\frac{-GMm}{R+h}

h = .14 R

b )

\frac{-GM}{R} + \frac{m\times(.351\times2GM) }{2R } = \frac{-GMm}{R+h} + 0

\frac{-0.649GMm}{R} = \frac{-GMm}{R+h}

h = .54 R

c ) least initial mechanical energy required at launch if the projectile is to escape Earth

= GMm / R + 1/2 m (2GM/R)

= 0

5 0
3 years ago
Explain what happens to the energy of a rock on the edge of a cliff as it falls from the
dolphi86 [110]

Answer:

A rock sitting on the edge of a cliff. If the rock falls, the potential energy will be converted to kinetic energy, as the rock will be moving. The potential energy decreases as the kinetic energy increases. The potential energy decreases as the kinetic energy decreases.

3 0
3 years ago
Other questions:
  • the gravitational force that earth exerts on the moon equals 2.03 x 10^20N. The moons mass is 7.35 x 10^22kg. What is the accele
    11·1 answer
  • When a force causes an object to move in the direction of the force blank occurs
    7·1 answer
  • A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. Calculate the energ
    11·1 answer
  • What is the rue of experimental designs that are used in scientific research?
    9·1 answer
  • What is the name of the ionic compound Cs2S
    12·2 answers
  • Jupiter’s Great Red Spot rotates completely every six days. If the spot is circular (not quite true, but a reasonable approximat
    6·1 answer
  • List the types of electromagnetic radiation in order of decreasing energy per photon.
    10·1 answer
  • 6. The momentum of a 30.0 g bird with a speed of 12 m.s-1 is 0.36 kg.m.s-1. What will be its momentum 12s later if a constant .0
    11·1 answer
  • Kepler’s laws of planetary motion describe each of the three laws
    5·1 answer
  • Which of the following is not a greenhouse gas?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!