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frozen [14]
2 years ago
5

This player along with the point guard, are considered the leaders of the team.

Physics
2 answers:
Ksivusya [100]2 years ago
8 0

Answer:

the center

Explanation:

i had it on my test

ser-zykov [4K]2 years ago
5 0

Answer:

Shooting guard I think

Explanation:

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What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make
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The transverse wave

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4 0
3 years ago
Suppose that you are taking a course in geometry. You are trying to determine whether two geometric shapes are identical, so you
Nataly_w [17]

Explanation:

Yes, in order to determine whether two geometric figures are identical or not we tend to rotate one of the figure clockwise or anti clock wise mentally. However, in clockwise rotation larger the angel more will be the time taken for instance, it will take longer to rotate 120° than to rotate 40°. Whereas in anti clockwise ration it will be vice versa.

3 0
3 years ago
How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the o
melisa1 [442]

Question:

A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes

How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the orbit of Mars is 12.6 light-minutes.

Answer:

S = 5.508 × 10¹¹m

V = 2.62 × 10⁸ m/s

Explanation:

The radius of the orbit of Jupiter, Rj is 43.2 light-minutes

radius of the orbit of Mars, Rm is 12.6 light-minutes

Distance travelled S = (Rj - Rm)

= 43.2 - 12.6 = 30.6 light- minutes

= 30.6 × (3 ×10⁸m/s) × 60 s

= 5.508 × 10¹¹m

time = 35mins = (35 × 60 secs)

= 2100 secs

speed = distance/time

V = 5.508 × 10¹¹m / 2100 s

V = 2.62 × 10⁸ m/s

7 0
3 years ago
PLEASE HELP ON EDGE I WILL GIVE U A BRAINLIST IF U GET IT RIGHT
quester [9]
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6 0
2 years ago
Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on
Romashka [77]

Answer:

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

Explanation:

According to Coulomb's law, the magnitude of  force between two point object having change q_1 and q_2 and by a dicstanced is

F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)

Where, \epsilon_0 is the permitivity of free space and

\frac{1}{4\pi\spsilon_0}=9\times10^9 in SI unit.

Before  dcollision:

Charges on both the sphere are q_1 and q_2, d=20cm=0.2m, and F_c=1.35\times10^{-4} N

So, from equation (i)

1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}

\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

\frac{q_1+q_2}{2}

d=20cm=0.2m, and F_c=1.406\times10^{-4} N

So, from equation (i)

1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}

\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}

\Rightarrow q_1+q_2=\pm5\times 10^{-8}

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)

\Rightarrow q_1=5\times 10^{-8}-q_2

The equation (ii) become:

(5\times 10^{-8}-q_2)q_2=6\times10^{-16}

\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0

\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}

From equation (iii)

q_1=2\times10^{-8}, 3\times10^{-8}

So, the magnitude of initial charges on both the sphere are 3\times10^{-8} Coulombs=0.03 \mu C and 2\times10^{-8} Colombs or 0.02 \mu C.

Considerion the nature of charges too,

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

4 0
3 years ago
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