Answer :
(a) The molecular equation will be,
![CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=CaCO_3%28aq%29%2B2HCl%28aq%29%5Crightarrow%20CaCl_2%28aq%29%2BH_2O%28l%29%2BCO_2%28g%29)
(b) The complete ionic equation in separated aqueous solution will be,
![Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D%28aq%29%2BCO_3%5E%7B2-%7D%28aq%29%2B2H%5E%7B%2B%7D%28aq%29%2B2Cl%5E%7B-%7D%28aq%29%5Crightarrow%20Ca%5E%7B2%2B%7D%28aq%29%2B2Cl%5E-%28aq%29%2BH_2O%28l%29%2BCO_2%28g%29)
(c) The net ionic equation will be,
![CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=CO_3%5E%7B2-%7D%28aq%29%2B2H%5E%7B%2B%7D%28aq%29%5Crightarrow%20H_2O%28l%29%2BCO_2%28g%29)
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The molecular equation will be,
![CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=CaCO_3%28aq%29%2B2HCl%28aq%29%5Crightarrow%20CaCl_2%28aq%29%2BH_2O%28l%29%2BCO_2%28g%29)
(b) The complete ionic equation in separated aqueous solution will be,
![Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D%28aq%29%2BCO_3%5E%7B2-%7D%28aq%29%2B2H%5E%7B%2B%7D%28aq%29%2B2Cl%5E%7B-%7D%28aq%29%5Crightarrow%20Ca%5E%7B2%2B%7D%28aq%29%2B2Cl%5E-%28aq%29%2BH_2O%28l%29%2BCO_2%28g%29)
In this equation,
are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
(c) The net ionic equation will be,
![CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)](https://tex.z-dn.net/?f=CO_3%5E%7B2-%7D%28aq%29%2B2H%5E%7B%2B%7D%28aq%29%5Crightarrow%20H_2O%28l%29%2BCO_2%28g%29)