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Zigmanuir [339]
3 years ago
12

Help me assiment will close after an hour ​

Chemistry
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer :

(a) The molecular equation will be,

CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)

(b) The complete ionic equation in separated aqueous solution will be,

Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)

(c) The net ionic equation will be,

CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The molecular equation will be,

CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)

(b) The complete ionic equation in separated aqueous solution will be,

Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)

In this equation, Ca^{2+}\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

(c) The net ionic equation will be,

CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)

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<em>Step 2</em>. Find the volume of the seawater

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<em>Step 3</em>. Find the mass of the seawater

Mass = 1895 L × (1.025 kg/1 L) = 1942 kg

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Answer:

15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs                                                                                              

Explanation:

Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation

         CF₂Cl₂ → CF2Cl  + Cl ⁻ .........(1)

From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical

From the question,

The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC

In one day the emission rate would be 59.5 x 24hours

                                                                  = 1428mg/day

In one year, the emission rate would be 1428mg/day x 365days

                                                                 =  521220mg/year

                                                                   = 521.220g/year/MVAC

Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is

                                                                    = 52122 x 10⁶g/year/MVAC

                                                                    = 52122 x 10³kg/year/MVAC

The molar mass of CF₂CL₂                       = 120.913g/mol

No of moles  of CF₂CL₂                              = mass/ molar mass

                                                                     = 52122 x 10⁶g / 120.913g/mol

                                                                      = 431 x 10⁶ moles of CF₂Cl₂

From equation 1,  since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that

431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,

Therefore, to find the mass of chlorine radical produced, we use the formula

No of moles of chlorine radical  = mass/ molar mass

431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical

431 x 10⁶ moles = mass/ 35.45g/mol

mass of chlorine =  431 x 10⁶ moles x 35.45 g/mol

                            =    15278.95 x 10⁶ g

In Kg, the mass    =   15,278.95 x 10³kg of cholrine radical

                             =   15.27895 x 10⁶ Kg of chlorine radical

                                                                                                 

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