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Lapatulllka [165]
3 years ago
14

For an object that is speeding up at a constant rate, how would the acceleration vs. time graph look?

Chemistry
2 answers:
katen-ka-za [31]3 years ago
4 0
A line that is diagonal and going up
asambeis [7]3 years ago
3 0

A horizontal line, not on the x-axis

"Answer for Apex"

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What is the volume of 0.2 moles of neon gas at STP?
eduard

Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

4 0
3 years ago
Read 2 more answers
Which representative element has the largest atomic radius ?
Vikki [24]

Answer:

francium

Explanation:

the atomic radius increases from top to bottom in a group, and decreases from left to right across a period.

7 0
3 years ago
In terms of bonds, what would the molecule C₆H₁₂ be classified as?
Colt1911 [192]

Answer:

Alkene

Explanation:

5 0
3 years ago
2-A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%
aleksandrvk [35]

The molecular formula :

C₆H₁₄O₃PF

<h3>Further explanation</h3>

Given

39.10% carbon, 7.67% hydrogen, 26.11%  oxygen, 16.82% phosphorus, and 10.30% fluorine.

Required

The molecular formula

Solution

mol ratio :

C = 39.1 : 12 = 3.258

H = 7.67 : 1 = 7.67

O = 26.11 : 16 = 1.632

P = 16.82 : 31 = 0.543

F = 10.3 : 19 = 0.542

Divide by 0.542

C = 6

H : 14

O = 3

P = 1

F = 1

The empirical formula :

C₆H₁₄O₃PF

(The empirical formula)n = the molecular formula

(C₆H₁₄O₃PF)=184.1

(6.12+14.1+3.16+31+19)n=184.1

(184)n=184.1

n = 1

3 0
3 years ago
A compound is 54.53% c, 9.15% h, and 36.32% o by mass. what is its empirical formula? the molecular mass of the compound is 132
Yakvenalex [24]
 <span>First - you need the empirical formula. 

So, assume you have 100 g of the compound. 

If so, you'll have 54.53 gram of C, 9.15 g of H and 36.32 g of O. Find the number of moles of each. 

54.53 g C (1 mole C / 12.01 g C) = 4.540 

9.15 g H (1 mole H / 1.008 g H) = 9.077 

36.32 g O (1 mole O / 15.9994 g O) = 2.270 

Take the smallest number found and divide the others by it to get the empirical formula. 

4.540/2.270 = 2. 
9.077/2.270 = 4. 
2.270/2.270 =1. 

So, that gives you the empirical formula of C2H4O. 

Find the weight of this compound. C = 12, H = 1, O = 16. So, C2H4O is 44 amu. 

132/44 = 3. 

So, 3 (C2 H4 O) = C6H12O3 = molecular formula.</span>
6 0
3 years ago
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