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3 years ago

In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)?

1 answer:

6 0

Answer: In metallic bonds, the mobile electrons surrounding the positive ions are called <u><em>dipole</em></u>.

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100 ml of a 0.300 m solution of agno3 reacts with 100 ml of a 0.300 m solution of hcl in a coffee-cup calorimeter and the temper

Olin [163]

Answer:

100 ml of a 0.300 m solution of agno3 reacts with 100 ml of a 0.300 m solution of hcl in a coffee-cup calorimeter and the temperature rises from 21.80 °c to 23.20 °c. Assuming the density and specific heat of the resulting solution is 1.00 g/ml and 4.18 j/g ∙ °c respectfully, what is the ΔH°rxn?

39.013 kJ/mol.

Explanation:

AgNO3(aq) + HCl(aq) --------------> AgCl(s) + HNO3(aq)

We can calculate the amount of heat (Q) released from the solution using the relation:

Q = m.c.ΔT,

Where, Q is the amount of heat released from the solution (Q = ??? J).

m is the mass of the solution (m of the solution = density of the solution x volume of the solution = (1.0 g/mL)(200 mL) = 200 g.

c is the specific heat capacity of the solution (c = 4.18 J/g∙°C).

ΔT is the difference in the T (ΔT = final temperature - initial temperature = 23.20 °C - 21.80 °C = 1.4 °C).

∴ Q = m.c.ΔT = (200 g)(4.18 J/g∙°C)(1.4 °C) = 1170.4 J.

∵ ΔH°rxn = Qrxn/(no. of moles of AgNO₃).

Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of AgNO₃)/(Volume of the solution (L)).

∴ no. of moles of AgNO₃

= (M)(Volume of the solution (L))

= (0.3 M)(0.1 L) = 0.03 mol.

∴ ΔH°rxn

= Qrxn/(no. of moles of AgNO₃)

= (1170.4 J)/(0.03 mol)

= 39013.33 J/mol

= 39.013 kJ/mol.

7 0

3 years ago

Someone help me please!!!

Montano1993 [528]

A. 6 moles

B. 9 moles

C. 3 moles

D. 20 moles

I think please check me, in case I am wrong

8 0

3 years ago

What is it called when moon is between setting and rising

miv72 [106K]

Answer:

I hope this link helps you.

Explanation:

http://astronomy.swin.edu.au/cosmos/P/Phases

4 0

3 years ago

A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law

zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

V₁ is the initial volume

T₁ is the initial temperature

V₂ is the final volume

T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

V₂ = $\frac{V_{1} }{T_{1} } x T_{2} = \frac{547}{331 } x 376$

V₂ = 621.4L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

Someone tell me if I'm right

ahrayia [7]

The answer of perimeter to this question is 36

3 0

2 years ago