Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
Answer:
You can dissolve about 1g of chloroform in a 100g of water; slightly less if the water is hot. This would not generally be considered 'soluble', but it's not entirely negligible either, depending on your purposes. chloroform is insoluble in water since it does not have any hydrophillic groups.
hope this helps you uwu
Answer:
Q = 1379.4 J
Explanation:
Given data:
Mass of water = 22 g
Initial temperature = 18°C
Final temperature = 33°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.
°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33°C - 18 °C
ΔT = 15°C
Q = 522 g ×4.18 J/g.°C× 15°C
Q = 1379.4 J
Answer:
5727 years or 5730 (rounded to match 3 sig figs) whichever one your teacher prefers
Explanation:
First Order decay has a half life formula of Half Life = Ln (2) / k = 0.693/K
Half-life = 0.693/k = 0.693/1.21 x10-4 = 5727 years or 5730 (rounded to match 3 sig figs)
This should be correct because if you google the half-life of 14 C it is ~ 5700 years
