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2 years ago

Elements have the same number of __as you move from left to right

Physics

1 answer:

Maksim231197 [3]2 years ago

6 0

Answer:

Explanation:

They have the same number of shells/ or energy levels!

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A string of 26 identical Christmas tree lights are connected in series to a 120 V source. The string dissipates 73 W. What is th

spin [16.1K]

To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,

$R_{eq}= \frac{V}{I}$

Here,

V = Voltage

I = Current

While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,

$P=VI \rightarrow I = \frac{P}{V}$

$I =0.608 A$

Applying Ohm's law

$R_{eq} = \frac{120V}{0.608A}$

$R_{eq} = 197.4\Omega$

Therefore the equivalent resistance of the light string is $197.4\Omega$

6 0

2 years ago

What is the right answer for this question is

shutvik [7]

The answer is 3
I hope I helped

7 0

2 years ago

A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be for a

andriy [413]

To solve this problem we will apply the concepts related to wavelength, as well as Rayleigh's Criterion or Optical resolution, the optical limit due to diffraction can be calculated empirically from the following relationship,

$sin\theta = 1.22\frac{\lambda}{d}$

Here,

$\lambda$ = Wavelength

d= Diameter of aperture

$\theta$ = Angular resolution or diffraction angle

Our values are given as,

$\theta = 11\°$

The frequency of the sound is $f = 9100 Hz$

The speed of the sound is $v = 343 m/s$

The wavelength of the sound is

$\lambda = \frac{v}{f}$

Here,

v = Velocity of the wave

f = Frequency

Replacing,

$\lambda = \frac{(343 m/s)}{(9100 Hz)}$

$\lambda = 0.0377 m$

The diffraction condition is then,

$sin\theta = 1.22\frac{\lambda}{d}$

Replacing,

$sin(11\°) = 1.22\frac{(0.0377 m)}{(d)}$

d = 0.24 m

Therefore the diameter should be 0.24m

6 0

2 years ago

A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Fin

egoroff_w [7]

Answer:

a) $A=5m/s^2$

b) $V=25m/s$

Explanation:

From the question we are told that:

Velocity $v=90km/h=25m/s$

Time $t=5.0s$

Generally From Newton's motion equation for Average acceleration is mathematically given by

$A=\frac{V-U}{t}$

Since its from Rest Therefore

$U=0$

$A=\frac{25m/s-0}{5s}$

$A=5m/s^2$

Generally the equation for Average Velocity is mathematically given by

$V=u+at$

$AT t=1.0s\\\\V=0+5(1)$

$V=5m/s$

$AT t=2.0s\\\\V=0+5(2)$

$V=10m/s$

$AT t=5.0s\\\\V=0+5(5)$

$V=25m/s$

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2 years ago

Dependent variable and the independent variable is ?

koban [17]

The two main variables in an experiment are the independent and dependent variable. An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific

7 0

2 years ago