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azamat
3 years ago
11

Which equation describes the sum of the vectors plotted below?

Physics
2 answers:
andrew-mc [135]3 years ago
6 0

It's the third one in the picture ...

r = 3x - 2y

Crazy boy [7]3 years ago
5 0

Explanation:

From the attached figure, OAB forms a triangle having,

a = (2,1)

b = (3,-2)

Vector, OA = 2x + y

Vector, AB = x - 3 y

The resultant can be calculated using triangular law of vector addition as :

r=OA+AB

r=2x+y+(x-3y)

r=3x-2y

So, the sum of the vectors plotted below is 3x-2y. Hence, the correct option is (c).

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Sort the chemical equations based on the chemical reactions they represent.
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                                         ABC    →    A  +  B  +  C

Specific Examples are as,

                                Water    →     Hydrogen + Oxygen

                                2 H₂O    →           2 H₂     +      O₂

               Calcium carbonate    →     Calcium oxide + Carbon dioxide

                            CaCO₃              →              CaO         +        CO₂

While, Synthetic reactions are said to be those reactions in which two or more reactants combine to form two or more products. The general reaction for synthetic reactions is as follow,

                                         A  +  B  +  C    →    ABC

Specific Examples are as,

                                  Iron + Oxygen     →     Iron Oxide

                                    2 Fe  +  3 O₂      →        2 Fe₂O₃

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4 0
3 years ago
Read 2 more answers
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The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.


The end point is the same as the starting point, so the displacement is 0 m.

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The container was lifted a height of 14 m
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2 years ago
Four charges of equal magnitude q = 2.16 µC are situated as shown in the diagram below. If d = 0.88 m, find the electric potenti
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Answer:

<em>The total potential (magnitude only) is 11045.45 V</em>

Explanation:

<u>Electric Potential </u>

The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by

\displaystyle V=\frac{kq}{r}

Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:

\displaystyle V_1=\frac{9\cdot 10^{9}\times -2.16\cdot 10^{-6}}{0.88}=-22090.91\ V

The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical

V_2=-22090.91\ V

The potential of the topmost charge is almost equal to the above computed, is only different in the sign:

V_3=+22090.91\ V

The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':

\displaystyle V_4=\frac{9\cdot 10^{9}\times 2.16\cdot 10^{-6}}{1.76}=+11045.45 \ V

The total electric potential in A is

V=-22090.91\ V-22090.91\ V+22090.91\ V+11045.45 \ V

V=-11045.45 \ V

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