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3 years ago

15

How do you calculate mass using Newton’s 2nd Law?

2 answers:

deff fn [24]3 years ago

5 0

The 2nd Law says F=ma, where F is the force in Newtons, m is mass and a is acceleration. Earth's gravity is an acceleration, 9.8m/s^2. So you can solve the equation for mass, m=F/a, or m=F/9.8 where you've measured the force (weight) in Newtons.

egoroff_w [7]3 years ago

4 0

To calculate from the mass by the during Newton's 2nd law are:

Newton's second law of motions is a states that the total net force will be acting on an object is to equal by the mass times acceleration.

With formula of m=f/a or a=f/m, and F=ma

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A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy

Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = $\sqrt{\frac{3g}{h} }$

c ) h = 1.34 m ( 4 $\pi ^{2}$ / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= ( $\pi r^{2} * \frac{h}{3}$ ) * 2 = $\frac{\pi r^{2} h }{6}$

The part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) = fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = $\frac{\alpha }{2} *$ $\frac{\pi r^{2} }{h}$ * a = ( force of gravity ) $\alpha * T\frac{r^{2} }{4} * x * g$

therefore a = $\frac{3g}{h} * x$

angular frequency ( w ) = $\sqrt{\frac{3g}{h} }$

C ) height of the each cone

$\frac{2\pi }{w} = 1$ therefore w = 2 $\pi$

back to the angular frequency : $\frac{3g}{h} = 4\pi ^{2}$

therefore h = 1.34 m ( 4 $\pi ^{2}$ / 3g )

4 0

3 years ago

A block of mass 10kg is moved at a constant speed through a horizontal distance of 4m, by applying a force 50N. How much work ha

algol13

Answer:

Explanation:

given that

mass = 10kg

distance = 4m

force = 50N

to calculate the workdone when the force is applied in the same direction of displacement

mathematically,

workdone = force × distance

Workdone = 50 × 4

workdone = 200 joules

2) to calculate the workdone at an angle of 30° with the displacement we apply the formula

workdone = force × distance × cos Ф

workdone = 50 × 4 × cos 30°

workdone = 200 × 0.866

workdone = 173 . 2 joules

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4 years ago

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) what is the electric

Alex_Xolod [135]

The expression for the magnitude of the electric field between two uniform conducting plates is

$E=\frac{V}{d}$

Here, V is potential difference between plates and d is separation between plates.

As the potential 6.00 cm from the zero volt plate (and 4.00 cm from the other) is 420 V.

Therefore,

$E = \frac{420 \ V}{6 \times 10^{-2} m } = 70 \times 10^2 \ V/m$

Thus, the electric field strength between the plates is 7000 V/ m

8 0

3 years ago

A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely

ad-work [718]

Answer:<em> 0.5kg</em>

Explanation:

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vivado [14]

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3 years ago