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Harlamova29_29 [7]
3 years ago
8

Which of the following locations would have the finest sedimentary particles?

Biology
1 answer:
Tamiku [17]3 years ago
5 0
The correct answer is mouth of a river

That's where the river slows down and particles start sedimenting. When the sediment is huge, deltas are formed.
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How does an enzyme change the activation energy for a reaction in a cell?
k0ka [10]

Answer:

The correct answer is option c. "Enzyme lowers the activation energy".

Explanation:

The activation energy is defined as the amount of energy needed for a reaction to take place. Enzymes catalyze reactions by lowering the activation energy, which speeds up the reaction and increases its rate. Enzymes put a substrate in its active site, which facilitates the reaction and makes more likely that it collides with its subsequent substrate.

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Glucose is a molecule that can move across the cell membrane. If the concentration of glucose is higher outside the cell than in
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It seems That teh molecules can move towards the membrane

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An extremely tiny parasite that can only reproduce if it is within a living being
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Answer:

Virus.

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Viruses can't reproduce without invading the cell of another living being.

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3 years ago
What are abiotic factors for pompie worms​
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Water, dirt, pebbles/gravel, clouds, temperature, sunlight. Hope this helps!
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3 years ago
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A large population of laboratory rats was allowed to breed randomly for a number of generations. In this population, a dominant
ivann1987 [24]

Answer:

Frequency of heterozygous animals with agouti fur  is 42 %

Explanation:

As per the Hardy Weinberg's equation -

q^2 represents the frequency of population with phenotype expressed by homozygous recessive genotype

p^ 2 represents the frequency of population with phenotype expressed by homozygous dominant genotype

and 2pq represents the frequency of population with phenotype expressed by homozygous recessive genotype

Given -

q^2 = 0.49\\q = 0.7

As per first principle of Hardy Weinberg's equilibrium

p + q = 1

Substituting the value of q in above equation, we get -

p = 1- 0.7 \\p = 0.3

As per second  principle of Hardy Weinberg's equilibrium

p^2 + q^2 + 2pq = 1\\

Substituting the given values in above equation, we get -

0.09 + 0.49 + 2pq = 1\\2pq = 1 - 0.58 \\2pq = 0.42

Frequency of heterozygous animals with agouti fur  is 42 %

5 0
2 years ago
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