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Dmitriy789 [7]
3 years ago
5

How many moles of water are produced when 3.25 moles of co2 are formed during the combustion of methyl alcohol (ch3oh)? 2ch3oh 3

o2 → 2co2 4h2o 1.62 moles 3.25 moles 6.50 moles 13.00 moles
Chemistry
2 answers:
aniked [119]3 years ago
8 0

Answer : The number of moles of water produced are, 6.50 moles

Explanation : Given,

Moles of carbon dioxide (CO_2) = 3.25 mole

The given balanced chemical reaction is :

2CH_3OH+3O_2\rightarrow 2CO_2+4H_2O

From the given balanced chemical reaction, we conclude that 2 moles of methyl alcohol react with 3 moles of oxygen to produced 2 moles of carbon dioxide and 4 moles of water.

When 2 moles of carbon dioxide is produced then 4 moles of water is also produced

Now, when 3.25 moles of carbon dioxide is produced then \frac{4}{2}\times 3.25=6.50moles of water is also produced

Therefore, the number of moles of water produced are, 6.50 moles

aliya0001 [1]3 years ago
4 0
<span>2CH</span>₃<span>OH  +  3O</span>₂<span>  →  2CO</span>₂ + <span> 4H</span>₂O

mole ratio of CO₂  :  H₂O  is  2  :  4 (simplified as 1 : 2)

∴ if moles of CO₂ = 3.25 moles

then moles of H₂O = 3.25 moles × 2
             
                              = 6.50 moles
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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride
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The question is incomplete, here is the complete question:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed? Be sure your answer has the correct number of significant digits.

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The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

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V_1=1.1mL\\n_1=1mol\\V_2=?L\\n_2=4mol

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