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umka21 [38]
3 years ago
11

1 2 3 4 5 6 7 8 9 10 Suna passes an electric current through a sample of clear, colorless, and odorless liquid. As the experimen

t continues, bubbles form, and the volume of liquid decreases. Suna collects samples of two colorless, odorless gases that bubble out of the liquid. One of the gases burns. Neither the original liquid nor the other gas burns. Which is the best explanation of her results
Chemistry
1 answer:
BaLLatris [955]3 years ago
8 0

The question is incomplete, the complete question is;

Suna passes an electric current through a sample of clear, colorless, and odorless liquid. As the experiment continues, bubbles form, and the volume of liquid decreases. Suna collects samples of two colorless, odorless gases that bubble out of the liquid. One of the gases burns. Neither the original liquid nor the other gas burns. Which is the best explanation of her results? The electric current changed some of the sample to gas even though the sample was not breaking down. Therefore, the original liquid is a compound. The electric current released a gas that was odorless and colorless, like the original sample. Therefore, the original liquid is an element. The sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound. The sample lost some of its volume, but the gas still had the same chemical makeup as the original sample. Therefore, the original liquid is an element.

Answer:

The sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound.

Explanation:

When electric current is passed through a compound, the compound may become broken down to release its constituents. We refer to this phenomenon as electrolysis. We can now say that the substance has been 'decomposed' electrolytically.

Since the original sample was decomposed to yield a gas that could burn and one that couldn't burn even though the original sample couldn't burn, then the original sample is a compound.

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Identify the term that matches each definition.
Katen [24]

Answer:

A,

C.

D.

B.

Explanation:

The front vent of a fume hood that assists and maintain proper air circulation is <u>Airfoil</u>

<u />

The horizontal flat surface area of the fume hood where experiments are being carried out is <u>Work  Surface.</u>

<u />

The main characteristics which demonstrate and describes how substances evaporate rapidly and readily into the thin air while producing a huge amount of vapor is known as <u>Volatile</u>

<u></u>

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6 0
3 years ago
In an energy diagram, the reactants are at a higher potential energy compared to the products. Which of the following best descr
mrs_skeptik [129]

Answer is (D) - It is exothermic and will have a negative enthalpy.


If the reactants are at a higher potential energy compared to the products, it means reactants have more energy than the products. That energy is released to the environment as heat. Due to the releasing of heat to the surrounding, the reaction is exothermic. Since the reaction is exothermic; the enthalpy of the reaction will be negative value.


3 0
4 years ago
the density of silver is 10,5 g/cm^3. what is the mass (in kilograms) of a cube of silver that measure .44 m on each side
GREYUIT [131]

Explanation:

First lets calculate the volume of the silver cube The length of a side = 0.62 m Volume

5 0
3 years ago
10. On the basis of the general solubility rules given
Crank
I think it’s c but I could be wrong
3 0
3 years ago
A chemist prepares a solution of potassium iodide (KI) by measuring out 88. umol of potassium iodide into a 200. mL volumetric f
max2010maxim [7]

The concentration in mol/L of the chemist's potassium iodide solution : = 4.4 x 10⁻⁴ M

<h3>Further explanation</h3>

Given

88. μmol of Potassium iodide

200. mL volumetric flask

Required

The concentration

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Conversion :

88. μmol = 88 . 10⁺⁶ mol = 8.8 10⁻⁵ mol

200 ml = 0.2 L

The molarity :

= n : V

= 8.8.10⁻⁵ : 0.2

= 4.4 x 10⁻⁴ M

4 0
3 years ago
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